Question

我正在创建我的投资组合，我将其模板从Bootstrap模板处理到django项目中，我需要使模板中的技能部分来自名为“技能”的模型，以便以后可以添加更多技能。列出模板中的项目和字体图标，以便哪个模型字段可以处理？请注意，并非所有图标都是字体图标。这是模板中的代码：

技能

    <div class="subheading mb-3">Programming Languages &amp; Tools</div>
    <ul class="list-inline dev-icons">

      <li class="list-inline-item">
        <i class="fab fa-html5"></i>
      </li>
      <li class="list-inline-item">
        <i class="fab fa-css3-alt"></i>
      </li>
      <li class="list-inline-item">
        <i class="fab fa-js-square"></i>
      </li>
      <li class="list-inline-item">
        <i class="fab fa-sass"></i>
      </li>

      <li class="list-inline-item">
        <i class="fab fa-python"></i>
      </li>

      <li class="list-inline-item">
        <img class="img-fluid img-profile  mx-auto mb-2" src="{% static 'img/sql.png' %}">
      </li>
      <li class="list-inline-item">
        <img id="logo" src="{% static 'img/logo.png' %}">
      </li>
    </ul>

    <div class="subheading mb-3">Duties & Responsibilities</div>
    <ul class="fa-ul mb-0">
      <li>
        <i class="fa-li fa fa-check"></i>
        Write reusable, testable, and efficient code.</li>
      <li>
        <i class="fa-li fa fa-check"></i>
        Design and implement of low-latency, high-availability, and performant applications.</li>
      <li>
        <i class="fa-li fa fa-check"></i>
        Integration of user-facing elements developed by front-end developers with server side logic.</li>
      <li>
        <i class="fa-li fa fa-check"></i>
        Implementation of security and data protection</li>
        <li>
        <i class="fa-li fa fa-check"></i>
        Integration of data storage solutions</li>
        <li>
        <i class="fa-li fa fa-check"></i>
        Work collaboratively with design team to understand end user requirements to provide technical solutions and for the implementation of new software features</li>
    </ul>
  </div>
</section>

Answer 1

您好，我建议您简单地创建一个具有Charfield字段的模型：

models.py：

class Skill(models.Model):
    skill = models.CharField(max_length=255, blank=False, null=False, unique=True)
    # name will make your skill easier to find in your admin
    name = models.CharField(max_length=255, blank=False, null=False, unique=True)

    def __str__(self):
        return self.name

在您看来，您将能够收集所有技能：

def skills_view(request):
    skills = Skills.objects.all()
    return render(request, "template.html", {
        'skills'=skills,
    }

在模板中显示技能：

{% for skill in skills %}
    <li class="list-inline-item">
            <i class="{{skill.skill}}"></i>
    </li>
{% endfor %}

如果我理解得很好，我会做这样的事情在管理员中注册模型以增加您的技能

如何处理我在Django中作为类模型的技能？

1 个答案: