我建立了一个查询，该查询在MySQL应用中运行时会显示所有预期结果。但是，当我在PHP代码中循环浏览时，结果只显示一行。
无论我如何处理SQL代码，它仍然会在我的MySQL应用程序中显示所有结果，但是由于某种原因，我的PHP代码中的某些内容导致了该问题，因此无法解决。
最后，尽管它显示了一行结果，但仍然出现错误
PHP警告：mysqli_fetch_assoc（）期望参数1为mysqli_result，在第144行“ ..中给出的字符串。错误。
我的查询在下面，其中$tID获取URL变量ID
SELECT *
FROM tbl_test_results tr
LEFT JOIN tbl_test_ordered tor
ON tr.testorderedID = tor.testorderedID
LEFT JOIN tbl_test t
ON tr.testID = t.testID
WHERE tor.testorderedID = '$tID'
ORDER BY t.test_name ASC
我的代码：
<!DOCTYPE html>
<html dir="ltr">
<head>
<?php include($_SERVER['DOCUMENT_ROOT'].'/gezond/includes/header_2019.php'); ?>
<title>gezond | cronkflies.com</title>
<style>
.tablesorter-pager .btn-group-sm .btn {
font-size: 1.2em; /* make pager arrows more visible */
}
</style>
<script type="text/javascript">
$(function() {
$("table").tablesorter({
theme : "bootstrap",
widthFixed: true,
// widget code contained in the jquery.tablesorter.widgets.js file
// use the zebra stripe widget if you plan on hiding any rows (filter widget)
// the uitheme widget is NOT REQUIRED!
widgets : [ "filter", "columns", "zebra" ],
widgetOptions : {
// using the default zebra striping class name, so it actually isn't included in the theme variable above
// this is ONLY needed for bootstrap theming if you are using the filter widget, because rows are hidden
zebra : ["even", "odd"],
// class names added to columns when sorted
columns: [ "primary", "secondary", "tertiary" ],
// reset filters button
filter_reset : ".reset",
// extra css class name (string or array) added to the filter element (input or select)
filter_cssFilter: [
'form-control',
'form-control',
'form-control', // select needs custom class names :(
'form-control',
'form-control',
'form-control'
]
}
})
.tablesorterPager({
// target the pager markup - see the HTML block below
container: $(".ts-pager"),
// target the pager page select dropdown - choose a page
cssGoto : ".pagenum",
// remove rows from the table to speed up the sort of large tables.
// setting this to false, only hides the non-visible rows; needed if you plan to add/remove rows with the pager enabled.
removeRows: false,
// output string - default is '{page}/{totalPages}';
// possible variables: {page}, {totalPages}, {filteredPages}, {startRow}, {endRow}, {filteredRows} and {totalRows}
output: '{startRow} - {endRow} / {filteredRows} ({totalRows})'
});
});
</script>
</head>
<body class="stretched">
<section id="content">
<div class="content-wrap">
<!-- <div class="section bottommargin-lg header-stick">
</div>-->
<div class="container">
<div class="row">
<div class="col-lg-12">
<div class="page-header">
</div>
<?php
if (!defined('DB_SERVER')) define('DB_SERVER', 'localhost');
if (!defined('DB_USER')) define('DB_USER', 'xxx');
if (!defined('DB_PASSWORD')) define('DB_PASSWORD', 'xxx');
if (!defined('DB_TABLE')) define('DB_TABLE', 'xxx');
// The procedural way
$mysqli = mysqli_connect(DB_SERVER, DB_USER, DB_PASSWORD, DB_TABLE);
$mysqli->set_charset("utf8");
$mysqli->query("SET NAMES 'utf8'");
if (mysqli_connect_errno($mysqli)) {
trigger_error('Database connection failed: ' . mysqli_connect_error(), E_USER_ERROR);
}
if (!isset($_GET['id']) || !is_numeric($_GET['id'])) {
die("Invalid ID specified.");}
else {
$tID = mysqli_real_escape_string($mysqli, $_GET['id']);
}
$query = "
SELECT *
FROM tbl_test_results tr
LEFT JOIN tbl_test_ordered tor
ON tr.testorderedID = tor.testorderedID
LEFT JOIN tbl_test t
ON tr.testID = t.testID
WHERE tor.testorderedID = '$tID'
ORDER BY t.test_name ASC ";
$result = mysqli_query($mysqli, $query) or trigger_error("Query Failed! SQL: $query - Error: ". mysqli_error($mysqli), E_USER_ERROR);
echo "
<table id='table_vluchten' class='table-bootstrap table-sm table-bordered table-striped' width='100%'>";
echo "<thead class='thead-inverse'>";
echo "<tr>";
echo "<th class='filter-false' data-sorter='false'> </th>
<th ><div align='left'>Test</div></th>
<th ><div align='left'>Result</div></th>
<th ><div align='left'>Units</div></th>
<th ><div align='left'>Low</div></th>
<th ><div align='left'>High</div></th>";
echo "</tr>";
echo "</thead>";
echo "<tbody>";
if($result) {
while($row = mysqli_fetch_assoc($result)) {
$test = $row['test_name'];
if(!isset($row['test_result'])) {
$result = $row['test_result_t'];
} else {
$result = $row['test_result'];
}
$low = $row['test_low'];
$high = $row['test_high'];
$units = $row['test_unit'];
echo "<tr >";
echo "<td style='width:50px;'><span style='font-size:14px;text-align: center;'><i class='fas fa-list-ul'></i></span></td>";
echo "<td style='width:200px'><span style='font-size:14px'>" .$test. "</span></td>";
echo "<td style='width:100px'><span style='font-size:14px'>" .$result. "</span></td>";
echo "<td style='width:100px'><span style='font-size:14px'>" .$units. "</span></td>";
echo "<td style='width:100px'><span style='font-size:14px'>" .$low. "</span></td>";
echo "<td style='width:100px'><span style='font-size:14px'>" .$high. "</span></td>";
echo "</tr>";
}
echo "</tbody>";
echo "</table>";
}
mysqli_close($mysqli);
?>
</div>
</div>
</div>
</div>
</section>
<script>
$(document).ready(function(){
$('[data-toggle="tooltip"]').tooltip();
});
</script>
</body>
</html>
答案 0 :(得分：0)
您的代码混乱。您正在混合很多过程样式和面向对象样式：
int main()
{
int i, score = 1, n;
float sum = 0.0, average; //<-------------changed to float
for(i=0; score>0; i++)
{
printf("Enter score (4-10) :");
scanf("%d", &score);
if(score>0){
sum = sum + score;
}
else{
break;
}
}
printf("You entered %d scores.\n", i);
average = sum / i;
printf("The average is: %f", average); //<--- changed to %f you can use &.2f to print 2 digits after .
return 0;
}
我建议选择一种或另一种，但不要一直混在一起。
但是@Qirel是您所要解决的特定问题的答案，那就是在此处重命名变量：
...
$mysqli->set_charset(... <-- object oriented style
$mysqli->query(... <-- object oriented style
if (mysqli_connect_errno(... <-- procedural style
mysqli_connect_error(... <-- procedural style