我需要使用JavaScript计算当前日期时间与用户输入日期时间之间的时差(以小时为单位)。这是我的代码:
var user_date = '31-03-2019';
var dep_time='12:30PM';
var datePieces = user_date.split("-");
var mydate=[datePieces[1] , datePieces[0] , datePieces[2]].join("-");
var todayDate = new Date();
var todayMonth = todayDate.getMonth() + 1;
var todayDay = todayDate.getDate();
var todayYear = todayDate.getFullYear();
if (todayDay < 10) {
todayDay = '0' + todayDay;
}
if (todayMonth < 10) {
todayMonth = '0' + todayMonth;
}
var todayDateText = todayMonth + "-" + todayDay + "-" + todayYear;
var inputToDate = Date.parse(mydate);
var todayToDate = Date.parse(todayDateText);
//console.log(inputToDate, todayToDate);
//console.log(user_date, todayDateText);
if (inputToDate > todayToDate) {
var date=new Date;
var hours = date.getHours();
var minutes = date.getMinutes();
var ampm = hours >= 12 ? 'pm' : 'am';
hours = hours % 12;
hours = hours ? hours : 12; // the hour '0' should be '12'
minutes = minutes < 10 ? '0'+minutes : minutes;
var strTime = hours + ':' + minutes + ' ' + ampm;
var timeStart = new Date(todayToDate + strTime);
var timeEnd = new Date(mydate + dep_time);
console.log(timeStart);
console.log(timeEnd);
var diff = (timeEnd - timeStart) / 60000; //dividing by seconds and milliseconds
var minutes = diff % 60;
var hours = (diff - minutes) / 60;
alert(hours);
} else {
}
我在这里得到输出NAN
。我同时具有用户输入和当前日期时间,并且需要HRS
中的时差。
答案 0 :(得分:1)
1)Date.parse方法将日期转换为自1970年1月1日起的毫秒数。请参见https://www.w3schools.com/Jsref/jsref_parse.asp,因此将用户输入日期转换为自1970年1月1日起的毫秒数。
2)在Javascript中,新Date()对象上的getTime()方法获取自1970年1月1日到当前时间为止经过的毫秒数。
3)因此,找到这些毫秒之间的差将得到毫秒之间的差。
4)因为1小时= 3600000 ms,所以要找到小时差,请将答案除以3600000,得到小时差。
解决方法如下:
<script>
"use strict";
var user_date = '31-03-2019 12:30 PM';
var datePieces = user_date.split("-");
var mydate=[datePieces[1] , datePieces[0] , datePieces[2]].join("-");
var todayDate = new Date();
var todayToDate = todayDate.getTime();
// In JavaScript, getTime() gets the number of milliseconds that have passed since January 1, 1970.
var inputToDate = Date.parse(mydate);
if (inputToDate > todayToDate) {
var diff = (inputToDate - todayToDate) / 3600000; //Since 1 h = 3600000 ms
alert(diff);
} else {
var diff = (todayToDate - inputToDate) / 3600000; //Since 1 h = 3600000 ms
alert(diff);
}
</script>