Question

我刚刚开始学习python，并且在执行最新项目时遇到无法修复的语法错误。

def adding_report():
    report_value = input('Input an integer to add to the total or "Q" to quit: ')
    while True:
        if report_value == "":
            report_value = input('Input an integer to add to the total or "Q" to quit: ')
        elif report_value.isdigit()：
            final_value = int(report_value) + int(report_value)
        elif report_value.lower() == "q"
            break
adding_report()

我希望此函数可以运行，并要求我向报告中添加一个整数，直到我输入可以中断循环的“ Q”为止，然后会出现一个显示报告最终值的结果，但是有一种语法运行此代码时出错。

elif report_value.isdigit()：
                           ^
SyntaxError: invalid character in identifier

Answer 1

您在行尾使用了https://ldap3.readthedocs.io/tutorial_operations.html#create-an-entry，而不是普通的冒号const arr = [ {jobid: "atA3Qi4BJu01VrUasiSX", id: "I1bncvyBsjbu7ePdPvYt", firstName: "Krishnakumar K R", Title: "design job", empname: "Rakesh"}, {jobid: "atA3Qi4BJu01VrUasiSX", id: "MDxEVS2hKftDrrPXsSWL", firstName: "test Candidate", Title: "design job", empname: "Rakesh"}, {jobid: "atA3Qi4BJu01VrUasiSX", id: "Mmu7oiAoCNcaU2ZWlLeS", firstName: "Rakesh", Title: "design job", empname: "Rakesh"}, {jobid: "atA3Qi4BJu01VrUasiSX", id: "m9SC2DbWxTrlTxJr12p0", firstName: "test user", Title: "design job", empname: "Rakesh"}, {jobid: "nCBNJ1yEn4EaGLR4BHDc", id: "1GMZpFhcOyDSt1KG4abK", firstName: "mohammed basheer", Title: "test job emp", empname: undefined}, {jobid: "nCBNJ1yEn4EaGLR4BHDc", id: "MDxEVS2hKftDrrPXsSWL", firstName: "test Candidate", Title: "test job emp", empname: undefined}, {jobid: "nCBNJ1yEn4EaGLR4BHDc", id: "Mmu7oiAoCNcaU2ZWlLeS", firstName: "Rakesh", Title: "test job emp", empname: undefined}, {jobid: "atA3Qi4BJu01VrUasiSX", id: "I1bncvyBsjbu7ePdPvYt", firstName: "Krishnakumar K R", Title: "design job", empname: "Rakesh"}, {jobid: "atA3Qi4BJu01VrUasiSX", id: "MDxEVS2hKftDrrPXsSWL", firstName: "test Candidate", Title: "design job", empname: "Rakesh"}, {jobid: "atA3Qi4BJu01VrUasiSX", id: "Mmu7oiAoCNcaU2ZWlLeS", firstName: "Rakesh", Title: "design job", empname: "Rakesh"}, {jobid: "atA3Qi4BJu01VrUasiSX", id: "m9SC2DbWxTrlTxJr12p0", firstName: "test user", Title: "design job", empname: "Rakesh"}, {jobid: "nCBNJ1yEn4EaGLR4BHDc", id: "1GMZpFhcOyDSt1KG4abK", firstName: "mohammed basheer", Title: "test job emp", empname: undefined}, {jobid: "nCBNJ1yEn4EaGLR4BHDc", id: "MDxEVS2hKftDrrPXsSWL", firstName: "test Candidate", Title: "test job emp", empname: undefined}, {jobid: "nCBNJ1yEn4EaGLR4BHDc", id: "Mmu7oiAoCNcaU2ZWlLeS", firstName: "Rakesh", Title: "test job emp", empname: undefined} ] const tmp = new Map() const rs = arr.reduce((acc, e) => { if(tmp.has(e.id)) { if (!tmp.get(e.id).includes(e.jobid)) { acc.push(e) tmp.set(e.id, [...tmp.get(e.id), e.jobid]) } } else { acc.push(e) tmp.set(e.id, [e.jobid]) } return acc }, []) console.log(rs)。

只需删除它，然后将其替换为普通冒号（并且不要忘记在缺少冒号的地方添加一个）：

Answer 2

尝试以下代码：

def adding_report():
    report_value = input(
        'Input an integer to add to the total or "Q" to quit: ')
    while True:
        if report_value == "":
            report_value = input(
                'Input an integer to add to the total or "Q" to quit: ')
        elif report_value.isdigit():
            final_value = int(report_value) + int(report_value)
        elif report_value.lower() == "q":
            break

adding_report()

您在：中使用了无效字符elif report_value.isdigit()：而不是:（这是完全不同的字符，也许您使用了不同的键盘布局？），但是您忘了再输入{ {1}}，后缀为

。

当标识符中的字符无效时，如何修复语法错误

2 个答案: