Question

我可以在字典上使用map lambda来打印3个或更多项目吗？

Answer 1

您无法访问dictionaries之类的x["title", "firstname", "lastname"]的多个元素；您需要为每个元素执行一次。

提取所需的元素后，可以将它们与' '.join结合起来：

def extract(person):
    return ' '.join(person[key] for key in ['title', 'firstname', 'lastname'])

fullnames_employees = [extract(person) for person in employees]
print(fullnames_employees)

输出：

['Mr Jonathan Calderon', 'Mr Christopher Hansen', 'Mrs Isabella Dorsey', 'Ms Barbara Baker']

Answer 2

除了lambda，我使用了简单的for循环：

for i in employees:
    print(i["title"]+ " " + i["firstname"] + " " + i["lastname"] )

结果：

Mr Jonathan Calderon
Mr Christopher Hansen
Mrs Isabella Dorsey
Ms Barbara Baker

或简单列表理解：

 print([i["title"]+ " " + i["firstname"] + " " + i["lastname"] for i in employees])

礼物：

['Mr Jonathan Calderon', 'Mr Christopher Hansen', 'Mrs Isabella Dorsey', 'Ms Barbara Baker']

Answer 3

您的lambda函数是正确的，但是从迭代元素获取数据的方式是错误的，无法访问，只能将每个元素数据加1并将其添加到字符串中并返回。 / p>

输入数据

employees = [
    {
        "email": "jonathan2532.calderon@gmail.com",
        "employee_id": 101,
        "firstname": "Jonathan",
        "lastname": "Calderon",
        "title": "Mr",
        "work_phone": "(02) 3691 5845"
    },
    {
        "email": "christopher8710.hansen@gmail.com",
        "employee_id": 102,
        "firstname": "Christopher",
        "lastname": "Hansen",
        "title": "Mr",
        "work_phone": "(02) 5807 8580"
    },
    {
        "email": "isabella4643.dorsey@gmail.com",
        "employee_id": 103,
        "firstname": "Isabella",
        "lastname": "Dorsey",
        "title": "Mrs",
        "work_phone": "(02) 6375 1060"
    },
    {
        "email": "barbara1937.baker@gmail.com",
        "employee_id": 104,
        "firstname": "Barbara",
        "lastname": "Baker",
        "title": "Ms",
        "work_phone": "(03) 5729 4873"
    }
]

代码

fullnames_employees = list(map(lambda x: '{} {} {}'.format(x["title"],x["firstname"],x["lastname"]), employees))

输出

['Mr Jonathan Calderon',
 'Mr Christopher Hansen',
 'Mrs Isabella Dorsey',
 'Ms Barbara Baker']

在字典上使用map lambda打印3个值

3 个答案: