我正在Netty Http服务器上工作。我已经创建并注册了处理程序。但我看不到请求击中处理程序
这是主要班级
public class NettyServer {
private int port;
private NettyServer(int port) {
this.port = port;
}
public static void main(String[] args) throws Exception {
int port;
if (args.length > 0) {
port = Integer.parseInt(args[0]);
} else {
port = 8080;
}
new NettyServer(port).run();
}
private void run() throws Exception {
EventLoopGroup bossGroup = new NioEventLoopGroup();
EventLoopGroup workerGroup = new NioEventLoopGroup();
try {
ServerBootstrap b = new ServerBootstrap();
b.group(bossGroup, workerGroup).channel(NioServerSocketChannel.class).childHandler(new ChannelInitializer<SocketChannel>() {
@Override
public void initChannel(SocketChannel ch) throws Exception {
ch.pipeline().addLast(new HttpMessageHandler(),new CalculatorOperationHandler());
}
}).option(ChannelOption.SO_BACKLOG, 128).childOption(ChannelOption.SO_KEEPALIVE, true);
ChannelFuture f = b.bind(port).sync();
f.channel().closeFuture().sync();
} finally {
workerGroup.shutdownGracefully();
bossGroup.shutdownGracefully();
}
}
}
HttpMessageHandler.java
public class HttpMessageHandler extends SimpleChannelInboundHandler<FullHttpRequest> {
protected void channelRead0(ChannelHandlerContext ctx, FullHttpRequest msg) throws Exception {
System.out.println("hello");
String uri = msg.uri();
HttpMethod httpMethod = msg.method();
HttpHeaders headers = msg.headers();
if (HttpMethod.GET == httpMethod) {
String[] uriComponents = uri.split("[?]");
String endpoint = uriComponents[0];
String[] queryParams = uriComponents[1].split("&");
if ("/calculate".equalsIgnoreCase(endpoint)) {
String[] firstQueryParam = queryParams[0].split("=");
String[] secondQueryParam = queryParams[1].split("=");
Integer a = Integer.valueOf(firstQueryParam[1]);
Integer b = Integer.valueOf(secondQueryParam[1]);
String operator = headers.get("operator");
Operation operation = new Operation(a, b, operator);
ctx.fireChannelRead(operation);
}
} else {
throw new UnsupportedOperationException("HTTP method not supported");
}
}
}
当我调用localhost:8080/calculate?a=1&b=2
这是怎么了?
答案 0 :(得分:2)
您的问题是由管道中缺少处理程序引起的。
目前,您的管道中只有2个处理程序:
HttpMessageHandler
,可处理FullHttpRequest
个对象CalculatorOperationHandler
,可处理Operation
个对象当来自浏览器的数据进入时,它作为ByteBuf
对象进入,但是您不处理该对象!
要从ByteBuf
转换为FullHttpRequest
,您需要在管道中添加其他可以执行此操作的处理程序。
您需要的第一个处理程序是HttpServerCodec
,此类将ByteBuf
对象转换为HTTP交换的一部分的对象,例如标头,请求正文的尾部标头。
然后,您需要添加一个HttpObjectAggregator
,它将上面的对象合并为一个FullHttpRequest
,因此您只需要处理1个对象。
ch.pipeline().addLast(
new HttpServerCodec(),
new HttpObjectAggregator(65536), // Handle POST/PUT requests up 64KB
new HttpMessageHandler(),
new CalculatorOperationHandler()
);
如果要查看任何层之间的流量,也可以添加new LoggingHandler(LogLevel.INFO)
。