我一直在做一个使用RSA算法加密.wav文件的项目,为此,我需要删除文件头以正确读取文件。我需要声音数据作为一个numpy数组。现在,我已经在网上搜索了此信息,但不了解文件头是什么以及如何在python3中删除它。期待提出建议。谢谢。
答案 0 :(得分:1)
binarySound = bytearray()
binaryHeader = bytearray()
with open("a2002011001-e02.wav",'rb') as f:
binaryHeader = f.read(44)
binarySound = f.read()
这应该是您要寻找的。这会将前44个字节(应该是标头)读入binaryHeader
变量,其余声音数据读入binarySound
变量。
要恢复音乐文件,您只需将这两个文件重新添加在一起
song = bytearray()
with open("header.bin","rb") as h:
song = h.read()
with open("data.bin","rb") as d:
song += d.read()
with open("new.wav","wb") as f:
f.write(song)
编辑:要在numpy数组中包含对OP的编辑,
import numpy
binarySound = {}
binaryHeader = {}
song = {}
with open("a2002011001-e02.wav",'rb') as f:
buffer = f.read(44)
binaryHeader = numpy.frombuffer(buffer,dtype=numpy.uint8)
buffer = f.read()
binarySound = numpy.frombuffer(buffer,dtype=numpy.uint8)
with open("header.bin","wb") as f:
f.write(binaryHeader)
with open("data.bin","wb") as f:
f.write(binarySound)
with open("header.bin","rb") as h:
song = h.read()
with open("data.bin","rb") as d:
song += d.read()
with open("new.wav","wb") as f:
song = numpy.array(song)
f.write(song.tobytes())