Question

我有两个看起来像这样的表。

表格申请人

LName    FName    MI
Adamson  Leon     R
Alfano   Vincent
Bost     Darrod   D

表ApplicantScore

ID    Name               Score
1     Adamson, Leon R.    89
2     Alfano, Vincent     99
3     Bost, Darrod D.     81
4     Smith, John         90
5     Chen, Lao           90
...

任何具有MI的名称都以句号结尾。

我需要使用表Applicant中的数据来从表ApplicantScore中检索信息。因此，最终看起来像

ID    Name               Score
1     Adamson, Leon R    89
2     Alfano, Vincent    99
3     Bost, Darrod D     81

我正在使用此SQL，但没有得到所需的内容。

select a.ID, a.name, a.score
from Applicant a
left join ApplicantScore b 
on (REPLACE(b.Name, ' ', '') = REPLACE(a.LName + ',' + a.FName + 
ISNULL(a.MI, ''), ' ', ''));

我得到的结果是：

ID    Name                Score
NULL  NULL                NULL
2     Alfano, Vincent     99
NULL  NULL                NULL

请帮助？

Answer 1

select b.id, b.name, b.score
from Applicant a
inner join ApplicantScore b
on (b.Name = a.LName | ', ' | a.FName | 
    CASE WHEN a.MI IS NULL THEN ''
         ELSE ' ' | a.MI
         END));

或按照@scsimon的建议在两端删除空格

select b.id, b.name, b.score
from Applicant a
inner join ApplicantScore b
on (REPLACE(b.Name, ' ', '') = 
    REPLACE(a.LName | ',' | a.FName | ISNULL(a.MI, ''), ' ', ''));

Answer 2

根据我的评论中的建议...

declare @Applicant table (LName varchar(64), FName varchar(64), MI char(1))
declare @ApplicantScore table (ID int identity (1,1), [Name] varchar(256), Score int)

insert into @Applicant
values
('Adamson','Leon','R'),
('Alfano','Vincent',null),
('Bost','Darrod','D')

insert into @ApplicantScore
values
('Adamson, Leon R',89),
('Alfano, Vincent',99),
('Bost, Darrod D',81),
('Smith, John',90),
('Chen, Lao',90)

select b.ID, b.name, b.Score
from @Applicant a
INNER JOIN @ApplicantScore b on 
replace(b.Name,' ','') = (RTRIM(a.LName) + ',' + RTRIM(a.FName) + ISNULL(a.MI,''))

SQL：拆分字符串以联接表已更新

2 个答案: