Question

我想以文本格式检索错误并将密钥，错误字典传递给表单，但它表明form.errors是不可迭代的

def signup(request):
forms={}
if request.method == 'POST':
    form = SignUpForm(request.POST)
    if form.is_valid():
        form.save()
        username = form.cleaned_data.get('username')
        raw_password = form.cleaned_data.get('password1')
        user = authenticate(username=username, password=raw_password)
        login(request, user)
        return redirect('/')
    else:
        if form.errors:
            for key,value in form.errors.items:
                forms[key]=BeautifulSoup(value,'html.parser').get_text() 
else:
    form = SignUpForm()
return render(request, 'signup.html',{'forms':forms})

在模板中是：

<script>
{% for key,value in forms.items %} 
    $(document).ready(function(){
        $('input[name={{key}}]').parent().addClass("alert-validate");
        $('input[name={{key}}]').parent().attr("data-validate", "{{value}}");
    });
    {% endfor %}
<script>

给出

错误

for key,value in form.errors.items:

Answer 1

应该为form.errors.items()，而不是form.errors.items

...
        if form.errors:
            for key,value in form.errors.items():
                forms[key]=BeautifulSoup(value,'html.parser').get_text()
...

无法从form.errors中检索键和值

1 个答案: