Question

我有以下Python脚本（以下摘录），该脚本读取E：\ Data \ Production目录下的所有日志文件，并查找某些正则表达式匹配项。

errors, tr, warnings = [], [], []

rootdir = 'E:\\Data\\Production'

for folder, dirs, files in os.walk(rootdir):
    for file in files:
        if file.endswith('.log'):
            fullpath = os.path.join(folder, file)
            with open(fullpath, 'r') as f:
                for line in f:
                    for match in re.finditer(r'.*' + daysdate + '(?!.*[->OK].*).*[Ee]rror.*', line):
                        errors.append(match.group(0))
                    for match in re.finditer(r'.*' + daysdate + '.*(?!.*deployed)(?!.*complete.*)(?!.*There are no.*)(?!.*disabled.*).*TR\d{4}.*', line):
                        warnings.append(match.group(0))
                    for match in re.finditer(r'.*' + daysdate + '.*(?!.*deployed)(?!.*[->OK])(?!.*complete.*)(?!.*There are no.*)(?!.*disabled.*).*TR\d{4}.*', line):
                        tr.append(match.group(0))

if errors == []:
    errors.append("No errors found.")
[...]
sendmail():
    "Errors:\n\n%s\n" % "\n".join(map(str, errors)) +
    "\Faulty:\n\n%s\n" % "\n".join(map(str, tr)) +
    "\Warnings:\n\n%s\n" % "\n".join(map(str, warnings))
sendmail()

此输出为：

Errors:
No errors found.
Faulty:
<the entire line containing the matched regex>
Warnings:
No errors found.

我想做的是添加发现错误的日志文件的完整路径，因此它将改为：

Errors:
No errors found.
Faulty:
<the entire line containing the matched regex>
Error found in file: E:\Data\Production\qwer\asdf\zxcv.log
Warnings:
No warnings found.

我假设我需要以某种方式附加fullpath变量，但是我对如何实现它感到茫然。

Answer 1

我相信你需要。

for match in re.finditer(r'.*' + daysdate + '.*(?!.*deployed)(?!.*[->OK])(?!.*complete.*)(?!.*There are no.*)(?!.*disabled.*).*TR\d{4}.*', line):
    tr.append(match.group(0) + "\n{0}".format(fullpath))

如果正则表达式匹配，则向消息添加文件路径

1 个答案: