Question

df %>% filter(Alive == "y", Campaign == "FEB_gems", 
              Level >= 7, Game_n == "GAME1")

#   Campaign Game_n    Class  Race Alignment Level Alive
# 1 FEB_gems  GAME1  fighter   elf        CG     7     y
# 2 FEB_gems  GAME1 sorcerer human        NN     7     y
# 3 FEB_gems  GAME1    rouge gnome        LG     7     y

需要将{ "ID": "5c9b2de495e8d81ef437539e", "WeightingFactor": "BIC", "TargetAmount": 1000, "FilterCondition": { "_cls": "ComplexFilter", "Condition": "AND", "Rules": [{ "_cls": "Filter", "Field": "MOODYSFOREIGNCURRENCYCEILINGRATING", "Operator": "in list", "Value": "A1,A2,A3" }, { "_cls": "Filter", "Field": "ASOFDATE", "Operator": "less or equal", "Value": "26 Nov 2028" }, { "_cls": "ComplexFilter", "Condition": "OR", "Rules": [{ "_cls": "Filter", "Field": "ASOFDATE", "Operator": "less or equal", "Value": "26 Nov 2028" }, { "_cls": "Filter", "Field": "ASOFDATE", "Operator": "less or equal", "Value": "26 Nov 2029" } ] } ], "Not": false } }重命名为"field"。请提出如何使用任何可用方法？

尝试了category和stringify。但这不起作用

预期输出：

replace

Answer 1

您可以在给定的JSON字符串中将字符串"field":替换为"category":。

var json = JSON.stringify({ field: { field: 'foo' } }),
    newJSON = json.replace(/"field":/g, '"category":');

console.log(JSON.parse(newJSON));

经典替代品

function replace(object, source, target) {
    return Object.assign(...Object.entries(object).map(([k, v]) => ({
        [k === source ? target : k]: v && typeof v === 'object'
            ? replace(v, source, target)
            : v
    })));
}

var object = { field: { field: 'foo' } },
    newObject = replace(object, 'field', 'category');

console.log(newObject);

Answer 2

我对Regex进行了性能测试，其中包括替换键和深度遍历JSON对象并替换键，结果发现Regex方法比深度遍历方法慢了65％。

下面是执行深度遍历的代码：

function deepTraverseAndReplace(o,sk,rk) {
    for (var key in o) {
        if (o[key ] !== null && typeof(o[key])=="object") {
            traverse(o[key],sk,rk);
        } else if( key == sk ) {
            o[rk] = o[key];
            delete(o[key]);
        }
    }
}



deepTraverseAndReplace(jsonObj,'Field','Category')

这是创建jsPerf的链接

如何在所有级别的JSON嵌套对象中重命名键？

2 个答案: