Question

我正在尝试使用固定方式抓取网页，但回电时不会解析项目，将不胜感激。...这里是代码

# -*- coding: utf-8 -*-
import scrapy
from ..items import EscrotsItem

class Escorts(scrapy.Spider):
    name = 'escorts'
    allowed_domains = ['www.escortsandbabes.com.au']
    start_urls = ['https://escortsandbabes.com.au/Directory/ACT/Canberra/2600/Any/All/']

    def parse_links(self, response):
        for i in response.css('.btn.btn-default.btn-block::attr(href)').extract()[2:]:
            yield scrapy.Request(url=response.urljoin(i),callback=self.parse)
        NextPage = response.css('.page.next-page::attr(href)').extract_first()
        if NextPage:
            yield scrapy.Request(
                url=response.urljoin(NextPage),
                callback=self.parse_links)

    def parse(self, response):
        for x in response.xpath('//div[@class="advertiser-profile"]'):
            item = EscrotsItem()
            item['Name'] = x.css('.advertiser-names--display-name::text').extract_first()
            item['Username'] = x.css('.advertiser-names--username::text').extract_first()
            item['Phone'] = x.css('.contact-number::text').extract_first()
            yield item

Answer 1

您的代码从start_urls调用url，然后转到parse函数。由于没有任何div.advertiser-profile元素，因此它实际上应该关闭而没有任何结果。因此，根本不会调用您的parse_links函数。

更改函数名称：

import scrapy


class Escorts(scrapy.Spider):
    name = 'escorts'
    allowed_domains = ['escortsandbabes.com.au']
    start_urls = ['https://escortsandbabes.com.au/Directory/ACT/Canberra/2600/Any/All/']

    def parse(self, response):
        for i in response.css('.btn.btn-default.btn-block::attr(href)').extract()[2:]:
            yield scrapy.Request(response.urljoin(i), self.parse_links)
        next_page = response.css('.page.next-page::attr(href)').get()
        if next_page:
            yield scrapy.Request(response.urljoin(next_page))

    def parse_links(self, response):
        for x in response.xpath('//div[@class="advertiser-profile"]'):
            item = {}
            item['Name'] = x.css('.advertiser-names--display-name::text').get()
            item['Username'] = x.css('.advertiser-names--username::text').get()
            item['Phone'] = x.css('.contact-number::text').get()
            yield item

我从scrapy shell中获取的日志：

In [1]: fetch("https://escortsandbabes.com.au/Directory/ACT/Canberra/2600/Any/All/")
2019-03-29 15:22:56 [scrapy.core.engine] INFO: Spider opened
2019-03-29 15:23:00 [scrapy.core.engine] DEBUG: Crawled (200) <GET https://escortsandbabes.com.au/Directory/ACT/Canberra/2600/Any/All/> (referer: None, latency: 2.48 s)

In [2]: response.css('.page.next-page::attr(href)').get()
Out[2]: u'/Directory/ACT/Canberra/2600/Any/All/?p=2'

cra草不解析项目

1 个答案: