Question

SELECT *
FROM   trips,
       dates
WHERE  places_number_on_flag > 0
       AND places_number > 0
       AND ( places_number - ( (SELECT Count(id)
                                FROM   resrv_customers
                                WHERE  trip = trips.id
                                       AND ow > 0)
                               + (SELECT Count(id)
                                  FROM   resrv_customers
                                  WHERE  trip = trips.id
                                         AND extra_seat = 1
                                         AND ow > 0) ) < 20 )
       AND dates.id = trips.trip_date
       AND dates.from_date > 2458553;

大约一分钟50秒后，它将返回5行。

我希望它更快。

Answer 1

一种优化方法是只运行一次子查询，并使用条件聚合来计算座位数：

SELECT *
FROM   trips
  JOIN dates on dates.id = trips.trip_date
WHERE  places_number_on_flag > 0
       AND places_number > 0
       AND ( places_number - ( (SELECT Count(id) + count(id) filter (where extra_seat = 1)
                                FROM   resrv_customers
                                WHERE  trip = trips.id
                                       AND ow > 0)) < 20 )
       AND dates.from_date > 2458553;

请注意，我用显式JOIN运算符替换了WHERE子句中的古老而脆弱的隐式联接。它对性能没有任何影响，只是更好的编码样式。

Answer 2

我们可以尝试使用resrv_customers表的联接重写查询，而不是使用昂贵的相关子查询：

WITH cte AS (
    SELECT
        trip,
        COUNT(CASE WHEN ow > 0 THEN 1 END) AS cnt1,
        COUNT(CASE WHEN extra_seat = 1 AND ow > 0 THEN 1 END) AS cnt2
    FROM resrv_customers
    GROUP BY trip
)

SELECT *
FROM trips t
INNER JOIN dates d
    ON t.trip_date = d.id
LEFT JOIN cte r
    ON r.trip = t.id
WHERE
    places_number > 0 AND
    places_number - (r.cnt1 + r.cnt2) < 20 AND
    d.from_date > 2458553;

在这里建立索引可能很棘手，因为您正在做SELECT *。要使Postgres使用任何索引，您可能必须做很多列介绍，即创建大索引。

Answer 3

尝试一下：

with rc_count as
(
    select trip, count(*) as ow_count, sum( (extra_seat = 1)::int ) as ow_count_with_extra_seat
    from resrv_customers
    where ow > 0
    group by trip    
)

SELECT *
FROM   trips
join   dates on dates.id = trips.trip_date
join   rc_count rc on trips.id = trip 
WHERE  places_number_on_flag > 0
       AND places_number > 0
       AND dates.from_date > 2458553
       and places_number - (ow_count + ow_count_with_extra_seat) < 20

如何优化此选择

3 个答案: