Question

我的文件路径为

falsefile：/// var / mobile / Containers / Data / Application / D4B6F6CD-5E5C-4459-90CC-0C649B3B31B8 / Documents / ExponentExperienceData /％2540hherax％252Fiia-mas-app-new // IIAMASATTCHMENTS / BD6FE729-70F1- 48B0-83EB-8E7D956E599E.MOV

因为文件扩展名将随着文件类型而变化文件路径也会更改

我该如何操作字符串以获取文件名

BD6FE729-70F1-48B0-83EB-8E7D956E599E"

在给定的示例中

路径和文件类型更改的第二个示例

falsefile：/// var / mobile / Containers / Data / Application / D4B6F6CD-5E5C-4459-90CC-0C649B3B31B8 / Documents / ExponentExperienceData /％2540ppphrx％252Fiia-mas-app-new // IIAMASATTCHMENTS / DD6FE729-60F2- 58B0-8M8B-8E759R6E547K.jpeg

Answer 1

您可以轻松完成

  let str="falsefile:///var/mobile/Containers/Data/Application/D4B6F6CD-5E5C-4459-90CC-0C649B3B31B8/Documents/ExponentExperienceData/%2540hherax%252Fiia-mas-app-new//IIAMASATTCHMENTS/BD6FE729-70F1-48B0-83EB-8E7D956E599E.MOV"


console.log(  str.split(".")[0].split("/").pop()
)

只记得拆分拆分弹出

Answer 2

切片/分割的某些变化会起作用

const str = 'falsefile:///var/mobile/Containers/Data/Application/D4B6F6CD-5E5C-4459-90CC-0C649B3B31B8/Documents/ExponentExperienceData/%2540hherax%252Fiia-mas-app-new//IIAMASATTCHMENTS/BD6FE729-70F1-48B0-83EB-8E7D956E599E.MOV'

console.log(
  str.slice(str.lastIndexOf("/")+1).split(".")[0]
)
// or

console.log(
  str.split("/").pop().split(".")[0]
)

Answer 3

例如，您可以使用正则表达式。我想到的第一件事是：

const filepath = 'falsefile:///var/mobile/Containers/Data/Application/D4B6F6CD-5E5C-4459-90CC-0C649B3B31B8/Documents/ExponentExperienceData/%2540hherax%252Fiia-mas-app-new//IIAMASATTCHMENTS/BD6FE729-70F1-48B0-83EB-8E7D956E599E.MOV'
const filenameWithoutExtension = filepath.match(/IIAMASATTCHMENTS\/(.*)\./)[1] // "BD6FE729-70F1-48B0-83EB-8E7D956E599E"

console.log(filenameWithoutExtension)

Answer 4

您可以使用如下所示的正则表达式：

function get_filename(str) {
  const regex = /\/([A-Z0-9\-_]+)\.[\w\d]+/gm;
  let m = regex.exec(str);
  return m[1];
}
console.log(
  get_filename(`falsefile:///var/mobile/Containers/Data/Application/D4B6F6CD-5E5C-4459-90CC-0C649B3B31B8/Documents/ExponentExperienceData/%2540ppphrx%252Fiia-mas-app-new//IIAMASATTCHMENTS/DD6FE729-60F2-58B0-8M8B-8E759R6E547K.jpeg`)
)

Answer 5

var str = "falsefile:///var/mobile/Containers/Data/Application/D4B6F6CD-5E5C-4459-90CC-0C649B3B31B8/Documents/ExponentExperienceData/%2540hherax%252Fiia-mas-app-new//IIAMASATTCHMENTS/BD6FE729-70F1-48B0-83EB-8E7D956E599E.MOV",
  re = /[\w|-]*\.\w*/
stringNameWithExt = str.match(re)
stringNameWithoutExt = str.match(re)[0].split(".")[0]
console.log(stringNameWithoutExt)

Answer 6

var filpath = "falsefile:///var/mobile/Containers/Data/Application/D4B6F6CD-5E5C-4459-90CC-0C649B3B31B8/Documents/ExponentExperienceData/%2540hherax%252Fiia-mas-app-new//IIAMASATTCHMENTS/BD6FE729-70F1-48B0-83EB-8E7D956E599E.MOV"
console.log(
  filpath.substring(filpath.lastIndexOf('/') + 1, filpath.length).substring(1, filpath.substring(filpath.lastIndexOf('/') + 1, filpath.length).lastIndexOf('.'))
)

Answer 7

如果知道要捕获的值的格式，则可以使用正则表达式获得更精确的匹配，然后在第一个捕获组中捕获值。

您可以使用/i标志使比赛区分大小写。

([A-Z0-9]+(?:-[A-Z0-9]+){4})\.\w+$

这将匹配：

(捕获组
- [A-Z0-9]+匹配1次以上character class中列出的内容
- (?:-[A-Z0-9]+){4}重复4次匹配连字符和1+倍字符类中列出的内容
)关闭捕获组
\.\w+$匹配一个点，一个字符char超过1倍，并断言字符串的结尾

Regex demo

let strs = [
  `falsefile:///var/mobile/Containers/Data/Application/D4B6F6CD-5E5C-4459-90CC-0C649B3B31B8/Documents/ExponentExperienceData/%2540hherax%252Fiia-mas-app-new//IIAMASATTCHMENTS/BD6FE729-70F1-48B0-83EB-8E7D956E599E.MOV`,
  `falsefile:///var/mobile/Containers/Data/Application/D4B6F6CD-5E5C-4459-90CC-0C649B3B31B8/Documents/ExponentExperienceData/%2540ppphrx%252Fiia-mas-app-new//IIAMASATTCHMENTS/DD6FE729-60F2-58B0-8M8B-8E759R6E547K.jpeg`
];
let pattern = /([A-Z0-9]+(?:-[A-Z0-9]+){4})\.\w+$/i;
strs.forEach(str => console.log(str.match(pattern)[1]));

处理包含文件路径的字符串，仅获取文件名

7 个答案: