一切正常,但是我想使用单选按钮值将$result['id'];
插入数据库。
JavaScript:
<script>
$(document).ready(function() {
$('input[type="radio"]').change(function() {
var stu_ans = $(this).val();
var stu_id = "<?php echo $_GET['sid'];?>";
var q_id = "<?php echo $result['id'];?>";
$.ajax({
url: "insert1.php",
method: "POST",
data: {
stu_ans: stu_ans,
stu_id: stu_id,
q_id: q_id
},
success: function(data) {
$('#result').html(data);
}
});
});
});
</script>
HTML:
<form role="form" id='formid' method="post" action="result.php?s_id=<?php echo $_GET['sid'];?>">
<?php
$number_question = 1;
$row = mysqli_query( $con, "select * from question where subject_id='$category' ORDER BY RAND()");
$rowcount = mysqli_num_rows( $row );
$remainder = $rowcount/$number_question;
$i = 0;
$j = 1; $k = 1;
?>
<h4>Total Question:-<?php echo $rowcount;?></h4>
<?php
while ( $result = mysqli_fetch_assoc($row) ) {
if ( $i == 0) echo "<div class='cont' id='question_splitter_$j'>";
?>
<div id='question<?php echo $k;?>' >
<p class='questions' id="qname<?php echo $j;?>" style="font-size:20px;font-weight:bold;color:green"> (<?php echo $k?>).<?php echo $result['que'];?></p>
<div class="table-responsive">
<table class="table">
<thead>
<tr>
<th></th>
<th></th>
<th></th>
<th></th>
<th></th>
<th></th>
</tr>
</thead>
<tbody>
<style>
input[type="radio"] {
-ms-transform: scale(1.5); /* IE 9 */
-webkit-transform: scale(1.5); /* Chrome, Safari, Opera */
transform: scale(1.5);
}
</style>
<tr>
<td>(A)<?php echo trim($result['o1']);?></td>
<td colspan="5"><input type="radio" value="<?php echo $result['o1'];?>" id='radio1_<?php echo $result['id'];?>' name='<?php echo $result['id'];?>'></td>
</tr>
<tr>
<td>(B)<?php echo $result['o2'];?>
</td>
<td colspan="5"><input type="radio" value="<?php echo $result['o2'];?>" id='radio1_<?php echo $result['id'];?>' name='<?php echo $result['id'];?>'/></td>
</tr>
<tr>
<td>(C)<?php echo $result['o3'];?></td>
<td colspan="5"><input type="radio" value="<?php echo $result['o3'];?>" id='radio1_<?php echo $result['id'];?>' name='<?php echo $result['id'];?>'/>
</td>
</tr>
<tr>
<td>(D)<?php echo $result['o4'];?></td>
<td colspan="5"><input type="radio" value="<?php echo $result['o4'];?>" id='radio1_<?php echo $result['id'];?>' name='<?php echo $result['id'];?>'/>
</td>
</tr>
</tbody>
</table>
</div>
<input type="radio" checked='checked' style='display:none' value="5" id='radio1_<?php echo $result['id'];?>' name='<?php echo $result['id'];?>'/>
<br/>
</div>
<?php
$i++;
if ( ( $remainder < 1 ) || ( $i == $number_question && $remainder == 1 ) ) {
echo "<button id='".$j."' class='next btn btn-success' type='submit'>Finish</button>";
echo "</div>";
} elseif ( $rowcount > $number_question ) {
if ( $j == 1 && $i == $number_question ) {
echo "<button id='".$j."' class='next btn btn-success' type='button'>Next</button>";
echo "</div>";
$i = 0;
$j++;
} elseif ( $k == $rowcount ) {
echo " <button id='".$j."' class='previous btn btn-success' type='button'>Previous</button>
<button id='".$j."' class='next btn btn-success' type='submit'>Finish</button>";
echo "</div>";
$i = 0;
$j++;
} elseif ( $j > 1 && $i == $number_question ) {
echo "<button id='".$j."' class='previous btn btn-success' type='button'>Previous</button>
<button id='".$j."' class='next btn btn-success' type='button' >Next</button>";
echo "</div>";
$i = 0;
$j++;
}
}
$k++;
}
?>
</form>
答案 0 :(得分:1)
在代码中保留SQL注入和安全性内容...
更改
var stu_ans=$(this).val();
针对:
var stu_and =$("input[name='<name_of_radio>']:checked").val();
这是从选定的单选按钮获取值的方法。
然后请!!!看看安全问题。
希望此代码对您有所帮助!