我正在设置规范,以测试作业在特定条件下是否调用方法。
这是我到目前为止所拥有的:
describe RandomJob do
context "when payload[:type] = MyModel" do
let!(:my_model) { create :my_model }
let!(:payload) { { type: "MyModel", id: my_model.id } }
context "when Model exists" do
it "calls MyModel.fire! with payload" do
RandomJob.perform_now(payload)
expect_any_instance_of(MyModel).to receive(:fire!).with(payload)
end
end
context "when Model does not exist" do
it "does not call MyModel.fire!" do
RandomJob.perform_now(payload)
expect_any_instance_of(MyModel).not_to receive(:fire!)
end
end
end
end
请确保我的测试方法有效。我这样设置我的工作:
class RandomJob < ApplicationJob
def perform(payload)
@payload = payload
fire_model!
end
private
def fire_model!
my_model&.fire! @payload
end
def my_model
MyModel.find(@payload[:id])
end
end
我希望第一个测试通过,第二个失败。但是,我的第一个测试失败了,而第二个测试却通过了。 我在做什么错了?
答案 0 :(得分:2)
您必须将期望放在之前perform_now
调用中。
context "when Model exists" do
it "calls MyModel.fire! with payload" do
expect_any_instance_of(MyModel).to receive(:fire!).with(payload)
RandomJob.perform_now(payload)
end
end
context "when Model does not exist" do
it "does not call MyModel.fire!" do
expect_any_instance_of(MyModel).not_to receive(:fire!)
RandomJob.perform_now(payload)
end
end