当我将#用作href值时,下拉菜单将起作用,但是当我具有链接时,下拉菜单将不起作用。
Bootstrap 4.3.1
我收到查询选择器错误:
SyntaxError:字符串与预期的模式不匹配。 所选元素
...
<li class="nav-item dropdown">
<a href="home/index" class="nav-link text-color-white dropdown-toggle" data-toggle="dropdown" role="button" aria-expanded="false">
Home
<i class="fa fa-search"></i>
</a>
<ul class="dropdown-menu" role="menu">
<li><a href="#" class="">Section 1</a></li>
<li><a href="#" class=""> Section 2</a></li>
<li><a href="#" class=""> Section 3</a></li>
</ul>
</li>
答案 0 :(得分:1)
这是Bootstrap中的一个已知问题,他们正在修复其下一发行版。 Source
A solution (many solutions exist in this thread)
apply plugin: 'com.android.application'
android {
compileSdkVersion 28
defaultConfig {
applicationId "com.myApp.mobile.pm.payday"
minSdkVersion 19
targetSdkVersion 28
versionCode 1
versionName "1.0"
testInstrumentationRunner "android.support.test.runner.AndroidJUnitRunner"
}
buildTypes {
release {
minifyEnabled false
proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-rules.pro'
}
}
}
dependencies {
implementation fileTree(dir: 'libs', include: ['*.jar'])
implementation "com.android.support:appcompat-v7:$rootProject.ext.supportLibraryVersion"
testImplementation 'junit:junit:4.12'
androidTestImplementation 'com.android.support.test:runner:1.0.2'
androidTestImplementation 'com.android.support.test.espresso:espresso-core:3.0.2'
implementation ("com.myApp.mobile.pm.common:app:$rootProject.ext.commonVersion") {
exclude group: 'com.fasterxml.jackson.annotation'
exclude group: 'com.fasterxml.jackson.core'
exclude group: 'com.fasterxml.jackson.databind'
}
annotationProcessor "com.jakewharton:butterknife-compiler:$rootProject.ext.butterknifeVersion"
annotationProcessor "android.arch.persistence.room:compiler:$rootProject.roomVersion"
}
下拉菜单需要一个ID,链接需要一个指向该ID的<li class="nav-item dropdown" id="parentDropdown">
<a href="home/index"
class="nav-link text-color-white dropdown-toggle"
data-toggle="dropdown"
data-target="#parentDropdown"
role="button"
aria-expanded="false">
Home
<i class="fa fa-search"></i>
</a>
<ul class="dropdown-menu" role="menu">
<li><a href="#" class="">Section 1</a></li>
<li><a href="#" class=""> Section 2</a></li>
<li><a href="#" class=""> Section 3</a></li>
</ul>
</li>
答案 1 :(得分:0)
在Ruby on Rails中,我们想声明一个链接,因此我们使用如下所示的内置link_to方法:
link_to(body, url, html_options = {})
在这种情况下,方法定义如下:
<%= link_to "Home", root_path, {class:"nav-link text-color-white dropdown-toggle", "data-toggle": "dropdown", role:"button", "aria-expanded": "false"} %>
来源:https://api.rubyonrails.org/classes/ActionView/Helpers/UrlHelper.html