我在二进制文件中有3条记录。当我修改记录并打开具有可读记录的文本文件时,具有修改后名称的记录只是重复且没有任何更改。此外,有时控制台会说该记录不存在,即使确实存在。 2个子程序用于创建二进制文件和带有二进制文件中记录的文本文件。
#include<stdio.h>
typedef struct {
char CNP[14];// CNP = Personal Identification Number
char nume[30]; // nume=name
int an; // an=year
int grupa; // grupa=group
int nrDisc; // nrDisc=number of classes
int note[20]; // note=grades
}STUDENT;
void creare(char*nume) { // creare=creation
FILE*f;
STUDENT s;
fopen_s(&f, nume, "wb");
if (!f)
printf("Eroare");
else {
printf("CNP:");
gets(s.CNP);
while (!feof(stdin)){
printf("Nume:");
gets(s.nume);
printf("An:");
scanf_s("%d", &s.an);
printf("Grupa:");
scanf_s("%d", &s.grupa);
printf("Nr. discipline:");
scanf_s("%d", &s.nrDisc);
for (int i = 0; i < s.nrDisc; i++)
{
printf("Nota[%d] este:", i);
scanf_s("%d", &s.note[i]);
}
fwrite(&s, sizeof(s), 1, f);
getchar();
printf("CNP:");
gets(s.CNP);
}
fclose(f);
}
}
void raport(char*nume_binar, char*nume_text) { // raport=report
FILE*f;
fopen_s(&f, nume_binar, "rb");
if (!f)
printf("Eroare");
else {
FILE*g;
STUDENT s;
fopen_s(&g, nume_text, "w");
fprintf(g," CNP Nume An Grupa Nr discipline\n\n");
while(fread(&s, sizeof(s), 1, f)==1)
{
fprintf(g,"%s %s %5d %9d %9d\n", s.CNP, s.nume, s.an, s.grupa, s.nrDisc);
for (int i = 0; i < s.nrDisc; i++)
{
fprintf(g, "Nota %d este:", i);
fprintf(g, "%d\n", s.note[i]);
}
fprintf(g, "\n");
}
fclose(g);
}
fclose(f);
}
void modificare(char*nume) { // modificare=modifying
FILE*f;
STUDENT s;
int grupa;
fopen_s(&f, nume, "rb+");
if (!f)
printf("Eroare");
else {
printf("Grupa:");
scanf_s("%d", &grupa);
while (!feof(stdin)) {
int g=0;
char nume[20];
fread(&s, sizeof(s), 1, f);
if (grupa == s.grupa) {
g = 1;
printf("Numele initial este:%s\n", s.nume);
printf("Noul nume este:");
getchar();
gets(nume);
fseek(f,ftell(f)-sizeof(s), 0);
fwrite(&s, sizeof(s), 1, f);
}
if (g == 0)
printf("Nu exista\n");
printf("Grupa:");
scanf_s("%d", &grupa);
}
fclose(f);
}
}
void main() {
char nume_fisier[] = "Student.dat";
char nume_fisier_txt[] = "Raport.txt";
//creare(nume_fisier);
//raport(nume_fisier, nume_fisier_txt);
modificare(nume_fisier);
}
答案 0 :(得分:0)
I used hibernate and jpa to obtain all my DB so it would be faster and easier.
I
@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
private Integer id;
private String img;
@NotEmpty
private String nombre;
@NotNull
private Integer precio;
@NotNull
private Integer unidades;
//bi-directional many-to-one association to Detalle
@JsonIgnore
@OneToMany(mappedBy="producto")
private List<Detalle> detalles;
//bi-directional many-to-one association to Cat
@JsonIgnore
@ManyToOne(fetch=FetchType.EAGER)
@JoinColumn(name="idcat")
private Cat cat;
//bi-directional many-to-one association to Tipoconsola
@JsonIgnore
@ManyToOne(fetch=FetchType.EAGER)
@JoinColumn(name="idconsola")
private Tipoconsola tipoconsola;
@Transient
private Integer idTC;
@Transient
private Integer idCategoria;