这是我正在使用的.csv文件:
B00123,55
B00783,35
B00898,67
我需要读取并存储在文件中输入的第一个值,例如B00123并将其存储到数组中。用户可以添加到文件中,因此它不是固定数量的记录。
到目前为止,我已经尝试了以下代码:
public class ArrayReader
{
static String xStrPath;
static double[][] myArray;
static void setUpMyCSVArray()
{
myArray = new double [4][5];
Scanner scanIn = null;
int Rowc = 0;
int Row = 0;
int Colc = 0;
int Col = 0;
String InputLine = "";
double xnum = 0;
String xfileLocation;
xfileLocation = "src\\marks.txt";
System.out.println("\n****** Setup Array ******");
try
{
//setup a scanner
/*file reader uses xfileLocation data, BufferedRader uses
file reader data and Scanner uses BufferedReader data*/
scanIn = new Scanner(new BufferedReader(new FileReader(xfileLocation)));
while (scanIn.hasNext())
{
//read line form file
InputLine = scanIn.nextLine();
//split the Inputline into an array at the comas
String[] InArray = InputLine.split(",");
//copy the content of the inArray to the myArray
for (int x = 0; x < myArray.length; x++)
{
myArray[Rowc][x] = Double.parseDouble(InArray[x]);
}
//Increment the row in the Array
Rowc++;
}
}
catch(Exception e)
{
}
printMyArray();
}
static void printMyArray()
{
//print the array
for (int Rowc = 0; Rowc < 1; Rowc++)
{
for (int Colc = 0; Colc < 5; Colc++)
{
System.out.println(myArray[Rowc][Colc] + " ");
}
System.out.println();
}
return;
}
public static void main(String[] args)
{
setUpMyCSVArray();
}
}
这会循环文件,但不会用任何数据填充数组。结果是:
****** Setup Array ******
[[D@42a57993
0.0
0.0
0.0
0.0
0.0
帮助!
答案 0 :(得分:2)
在尝试将ID转换为Double的第一行中,实际上发生了NumberFormatException。所以我修改了程序,对我有用。
import java.io.BufferedReader;
import java.io.FileReader;
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;
public class ArrayReader
{
static String xStrPath;
static Map<String,Double> myArray = new HashMap<>();
static void setUpMyCSVArray()
{
Scanner scanIn = null;
int Rowc = 0;
int Row = 0;
int Colc = 0;
int Col = 0;
String InputLine = "";
double xnum = 0;
String xfileLocation;
xfileLocation = "/Users/admin/Downloads/mark.txt";
System.out.println("\n****** Setup Array ******");
try
{
//setup a scanner
/*file reader uses xfileLocation data, BufferedRader uses
file reader data and Scanner uses BufferedReader data*/
scanIn = new Scanner(new BufferedReader(new FileReader(xfileLocation)));
while (scanIn.hasNext())
{
//read line form file
InputLine = scanIn.nextLine();
//split the Inputline into an array at the comas
String[] inArray = InputLine.split(",");
//copy the content of the inArray to the myArray
myArray.put(inArray[0], Double.valueOf(inArray[1]));
//Increment the row in the Array
Rowc++;
}
}
catch(Exception e)
{
System.out.println(e);
}
printMyArray();
}
static void printMyArray()
{
//print the array
for (String key : myArray.keySet()) {
System.out.println(key + " = " + myArray.get(key));
}
return;
}
public static void main(String[] args)
{
setUpMyCSVArray();
}
}
输出:
答案 1 :(得分:1)
代码无法读取任何内容,因此文件路径不正确。请给它绝对的文件路径。
scanIn = new Scanner(new BufferedReader(new FileReader(xfileLocation)));
答案 2 :(得分:0)
我使用opencsv库从csv中读取。
import com.opencsv.CSVReader;
public class CSV {
private static String file = <filepath>;
private static List<String> list = new ArrayList<>();
public static void main(String[] args) throws Exception {
try {
CSVReader reader = new CSVReader(new FileReader(file));
String[] line;
while ((line = reader.readNext()) != null) {
list.add(line[0]);
}
Object[] myArray = list.toArray();
System.out.println(myArray.length);
System.out.println(myArray[0]);
} catch (Exception e) {
e.printStackTrace();
}
}
}
输出打印如下
3
B00123