Question

通过使用查询，我正在数组中获取结果，我想在一个数组中获取此数据，我正在按照以下方式获得结果

Array
(
    [0] => stdClass Object
        (
            [id] => 2
            [full_name] => amit sharma
        )

    [1] => stdClass Object
        (
            [id] => 1
            [full_name] => amit
            )

)

我尝试了以下代码，但对我不起作用，我错了，这是我的代码

$sql = "//select query";
$result= $this->db->query($sql)->result();
$total=count($result);
if($total>0)
{
    $data=array();
    foreach($result as $records)
    {
        $data[]=$records;
    }
    echo "<pre>";print_R($data);
}

Answer 1

只需使用json_encode()和json_decode()

我已经创建了与您的示例相同的对象，只是忽略了以下代码：

$result = [$objOne, $objTwo];

使用您的$result

Json对其进行编码和解码，以得到一个关联数组。

代码：

<?php
$objOne = new stdClass();
$objOne->id = 2;
$objOne->full_name = 'amit sharma';

$objTwo = new stdClass();
$objTwo->id = 1;
$objTwo->full_name = 'amit';

$result = [$objOne, $objTwo];
$arr = json_decode(json_encode($result), TRUE);
echo '<pre>';
print_r($result);
echo '</pre>';
echo '<pre>';
print_r($arr);
echo '</pre>';
?>

输出：

Array
(
    [0] => stdClass Object
        (
            [id] => 2
            [full_name] => amit sharma
        )

    [1] => stdClass Object
        (
            [id] => 1
            [full_name] => amit
        )

)

Array
(
    [0] => Array
        (
            [id] => 2
            [full_name] => amit sharma
        )
    [1] => Array
        (
            [id] => 1
            [full_name] => amit
        )

)

Answer 2

您可以轻松地循环它并获取数组中的值，如下所示。

$post_id = array((object) (array(
   'id' => 1,
   'full_name' => "Amit Sharma",
)), (object) (array(
   'id' => 2,
   'full_name' => "Amit",
)), (object) (array(
   'id' => 3,
   'full_name' => "Amit Rohan",
)));

foreach ($post_id as $key => $value) 
{   $result[] = array("id"=>$value->id, "full_name"=>$value->full_name);    }

echo "<pre>";print_r($result);

从PHP内部数组中获取数据

2 个答案: