我一直在尝试在switch语句条件内连续打印引脚3的PWM输出，但只打印一次。我可以连续在串行监视器中打印它直到遇到第二个条件吗？或使用while循环？还是其他？
这是我的代码，我也有一个具有类似功能的代码，但是如果不使用它，它仍然只打印一次
void loop() {
// if there's any serial available, read it:
while (Serial.available() > 0) {
int InitVal = Serial.parseInt();
int red = Serial.parseInt();
switch(InitVal) {
case 1:
if (Serial.read() == '\n') {
analogWrite(redPin, red);
Serial.println(red);
Serial.write(red);
}
break;
case 0:
analogWrite(redPin, 0);
Serial.println(0);
Serial.write(0);
break;
}
}
}
我打算将此阶段与GUI进行中间阶段。 GUI将ASCII发送到arduino，然后将输出值发送到GUI。 例子
1.GUI发送[1,123]：1 = switch语句的触发点； 123 = PWM值。
修改后的代码：卡在最后一个while循环中，也许我可以在arduino中使用线程处理功能，以便最后一个while循环会得到满足/不满意？
void loop() {
int InitVal = 0;
// if there's any serial available, read it:
while (Serial.available() > 0) {
int InitVal = Serial.parseInt();
int red = Serial.parseInt();
switch(InitVal) {
case 1:
if (Serial.read() == '\n') {
InitVal = 1;
//analogWrite(redPin, red);
//Serial.println(red);
// Serial.write(red);
}
break;
case 0:
InitVal = 0;
//analogWrite(redPin, 0);
//Serial.println(0);
//Serial.write(0);
break;
}
if (InitVal) /* when enabled, blink leds */ {
delay(20);
while (InitVal == 1) /* loop forever */{
Serial.println(red);
Serial.write(red);
delay(20);
}
}
}
}
答案 0 :(得分：0)
我放弃了Serial.parseInt（）函数，删除了开关语句，然后按照@Arno Bozo建议在http://forum.arduino.cc/index.php?topic=396450.0上进行本教程的同时进行串行侦听 我想出了我想要的东西，这是代码
const int redPin = 3;
const byte numChars = 32;
char receivedChars[numChars];
char tempChars[numChars]; // temporary array for use when parsing
// variables to hold the parsed data
boolean newData = false;
int InitVal = 0; // change to init value or red
int red = 0;
void setup() {
// initialize serial:
Serial.begin(9600);
// make the pins outputs:
pinMode(redPin, OUTPUT);
}
void loop() {
recvWithStartEndMarkers();
if (newData == true) {
strcpy(tempChars, receivedChars);
// this temporary copy is necessary to protect the original data
// because strtok() used in parseData() replaces the commas with \0
parseData();
One();
newData = false;
}
else {
Zero();
}
}
///////////////////// ///////////////////// /////////////////////
void recvWithStartEndMarkers() {
static boolean recvInProgress = false;
static byte ndx = 0;
char startMarker = '<';
char endMarker = '>';
char rc;
while (Serial.available() > 0 && newData == false) {
rc = Serial.read();
if (recvInProgress == true) {
if (rc != endMarker) {
receivedChars[ndx] = rc;
ndx++;
if (ndx >= numChars) {
ndx = numChars - 1;
}
}
else {
receivedChars[ndx] = '\0'; // terminate the string
recvInProgress = false;
ndx = 0;
newData = true;
}
}
else if (rc == startMarker) {
recvInProgress = true;
}
}
}
///////////////////// ///////////////////// /////////////////////
void parseData() { // split the data into its parts
char * strtokIndx; // this is used by strtok() as an index
strtokIndx = strtok(tempChars,","); // get the first part - the string
InitVal = atoi(strtokIndx); // copy it to messageFromPC
strtokIndx = strtok(NULL, ","); // this continues where the previous call left off
red = atoi(strtokIndx); // convert this part to an integer
}
///////////////////// ///////////////////// /////////////////////
void One() {
if (InitVal == 0){
delay(20);
Serial.println(0);
delay(20);
}
}
///////////////////// ///////////////////// /////////////////////
void Zero() {
if (InitVal == 1){
delay(20);
Serial.println(red);
delay(20);
}
}
摘要中，代码的工作方式如下
1。在串行监视器中，发送此<1,123>：1 = switch语句的触发点； 123 = PWM值。
答案 1 :(得分：0)
我在这里发布了完善的代码。该体系结构可以重新用于串行处理。我已将它写为我遇到的人以及正在学习arduino的人的例子。
我对避免延误的方式进行了评论和解释。此处用于每1秒打印一次pwm的当前值，而不会延迟（1000）停止。
#include <Arduino.h>
// with schedule(f,i) , the function f() will be called every i ms
// schedule(f,i) lines are put in loop() function
// f is of type void f(void)
#define schedule(f,i) {static unsigned long l=0;unsigned long c=millis();if((unsigned long)(c-l)>=i){l=c;f();}}
const int ledPin = 13;
void setup() {
Serial.begin(9600);
pinMode(ledPin, OUTPUT);
}
boolean newCommandHasArrived=false, newParsedCommand=false;
String personalSerialBuffer=""; // char[] would be better; but String are so convenient
enum ECommand {ecmdNoPwm=0, ecmdPwm=1, ecmdBad=10 };
ECommand cmd=ecmdNoPwm;
int cmdArg=0;
boolean readSerialBuffer(String &personalSerialBuffer);
boolean parseCommand(String &apersonalSerialBuffer, ECommand &acmd, int &acmdArg);
void executeCommand(ECommand acmd, int &acmdArg);
void printCurrentValue() {Serial.println(String("cval:") + cmdArg);}
void loop() {
// transfer serial buffer in personal buffer
newCommandHasArrived = readSerialBuffer(personalSerialBuffer);
if (newCommandHasArrived) {
newCommandHasArrived = false;
newParsedCommand = parseCommand(personalSerialBuffer, cmd, cmdArg);
}
if (newParsedCommand) {
newParsedCommand = false;
executeCommand(cmd, cmdArg);
}
// I print current value every 1000ms
//delay(1000); // you can often use delay without pb, but it is a bad usage
// Here I provide you with a quick way to execute a task every 1000ms
{
const unsigned long delayBetweenExecution=1000;
static unsigned long lastTime=0;
unsigned long current = millis();
// note that C++ says that overflow on unsigned is well defined
// it calculates modulo arithmetic
if ((unsigned long)(millis() - lastTime) >= delayBetweenExecution) {
lastTime = current;
Serial.println(String("cval:") + cmdArg);
}
}
// We can make it shorter thanks to a macro:
// but you have to define a void function(void) that uses only global variable
// because it has no argument :
// void printCurrentValue() {Serial.print(String("cval:") + cmdArg);}
//schedule(printCurrentValue, 1000);
}
boolean readSerialBuffer(String &personalSerialBuffer) {
if (Serial.available() > 0) {
personalSerialBuffer.concat(Serial.readString());
}
// the frame is considered finished, if it ends with \n
if (personalSerialBuffer.endsWith("\n"))
return true;
else
return false;
}
boolean parseCommand(String &apersonalSerialBuffer, ECommand &acmd, int &acmdArg) {
// format [ 1, 123]\n
// I omit [ then I read first int : 1
// Note: I cannot detect if no int is found because it will return 0 that is a valid cmd
int readCmd = apersonalSerialBuffer.substring(1).toInt();
// conversion readCmd to acmd
switch (readCmd) {
case 0:
acmd = ecmdNoPwm; break;
case 1:
acmd = ecmdPwm; break;
default:
Serial.println(String("new command unknown: ") +
apersonalSerialBuffer);
apersonalSerialBuffer = "";
return false;
}
// find beginning of 2nd part, separated by ','
int sepPos = apersonalSerialBuffer.indexOf(',');
// no ',' : indexOf returns -1
if (sepPos == -1) {
Serial.println(String("new command could not be parsed: ") +
apersonalSerialBuffer);
apersonalSerialBuffer = "";
return false;
}
// Note: I cannot detect if no int is found because it will return 0 that is a valid cmd
acmdArg = apersonalSerialBuffer.substring(sepPos+1).toInt();
// All is fine
// I have to reset buffer before leaving
apersonalSerialBuffer = "";
return true;
}
void executeCommand(ECommand acmd, int &acmdArg) {
switch(acmd) {
case ecmdNoPwm:
// I erase acmdArg
acmdArg = 0;
analogWrite(ledPin, acmdArg);
Serial.println("cmd no pwm");
break;
case ecmdPwm:
analogWrite(ledPin, acmdArg);
Serial.print("cmd pwm:"); Serial.println(acmdArg);
break;
default:
analogWrite(ledPin, 0);
Serial.println("Bad cmd");
}
}