从网站中提取链接和项目名称并打印这些列表

时间:2019-03-28 10:16:31

标签: python python-3.x web-scraping beautifulsoup

我是python编程的初学者,我正在使用bs4模块在​​Python中练习网页抓取。 我正在尝试从网站中提取一些信息,如下所示。

每个显示的列表显示为空。请告诉我我在哪里做错了。

import requests
from bs4 import BeautifulSoup as bs    

res = requests.get('https://www.flipkart.com/samsung-mobile-store?otracker=nmenu_sub_Electronics_0_Samsung')
soup = bs(res.content, 'lxml')

names = [item['title'] for item in soup.select('._2cLu-1 a')]

links = [item['href'] for item in soup.select('._2cLu-l a')]

ratings = [item.text for item in soup.select('.hGSR34 div')]

print(names)
print(links)
print(ratings)

2 个答案:

答案 0 :(得分:0)

要获得名称,链接和等级的Seaprate列表,请创建其列表并相应地添加:

from bs4 import BeautifulSoup as bs

res = requests.get('https://www.flipkart.com/samsung-mobile-store?otracker=nmenu_sub_Electronics_0_Samsung')
soup = bs(res.content, 'html.parser')

namesList = []
linksList = []
ratingsList = []

namesLinks = soup.find_all('a', class_ ='Zhf2z-')    
ratings = soup.find_all('div', class_ ='hGSR34')

for rat in ratings:
    ratingsList.append(rat.text)

for nameLnk in namesLinks:
    namesList.append(nameLnk.get('title', 'No title available'))
    linksList.append(nameLnk.get('href', 'No href available'))

print(namesList)
print(linksList)
print(ratingsList)

输出

['Samsung Galaxy A30 (Black, 64 GB)', 'Samsung Galaxy M20 (Ocean Blue, 32 GB)', 'Samsung Galaxy M10 (Blue, 16 GB)', ... ]

['/samsung-galaxy-a30-black-64-gb/p/itmfec2hqbxcmbzn?pid=MOBFE4CSBDN9XETN&lid=L ...]

['4.4', '4.1', '4.1', '4.6', '4.3', '4.2', '4.3', '4.1', '4.2', '4.2', '4.2', '4.4', ... ]

编辑

我还将研究一种将设备名称,其链接和等级一起打印的方法:

使用zip()

from bs4 import BeautifulSoup as bs

res = requests.get('https://www.flipkart.com/samsung-mobile-store?otracker=nmenu_sub_Electronics_0_Samsung')
soup = bs(res.content, 'html.parser')

names = soup.find_all('a', class_ ='Zhf2z-')
ratings = soup.find_all('div', class_ ='hGSR34')

for nm, rat in zip(names, ratings):
    print("Device: {}, Link: {}, Rating: {}".format(nm.get('title', 'no title avialable'), nm.get('href', 'href not available'), rat.text))

输出

Device: Samsung Galaxy A30 (Black, 64 GB) Link: /samsung-galaxy-a30-black-64-gb/pN&lid= .. .. cid=MOBFE4CSBDN9XETN Rating: 4.4
Device: Samsung Galaxy M20 (Ocean Blue, 32 GB) Link: /samsung-galaxy-m20-ocean-blue-32-gb/p/.. .. JGFRTYMC Rating: 4.1
Device: Samsung Galaxy M10 (Blue, 16 GB) Link: /samsung-galaxy-m10-blue-16-gb/p/.. .. 6JYE8YG Rating: 4.1
Device: Samsung Galaxy M30 (Gradation Black, 64 GB) Link:/samsung-galaxy-m30-gradation-black-64-gb/p/.. .. CDPXGUP Rating: 4.6

答案 1 :(得分:0)

是的,您可以使用select轻松地做到这一点。请注意,有1个项目没有评分。您无需在两个不同的情况下访问相同的元素来生成名称和链接。

import requests
from bs4 import BeautifulSoup as bs

url = 'https://www.flipkart.com/samsung-mobile-store?otracker=nmenu_sub_Electronics_0_Samsung'
r = requests.get(url)
soup = bs(r.content, 'lxml')

names, links = zip(*[(item['title'], 'https://www.flipkart.com' + item['href']) for item in soup.select('._2cLu-l')])
ratings = [item.text for item in soup.select('.niH0FQ  .hGSR34')]  # 1 rating missing for a product

print(list(names))
print(list(links))
print(ratings)

如果要将它们加入数据框并考虑缺少的评分,可以使用以下内容(如果需要,可以将if else扩展到前两个项目)

import requests
from bs4 import BeautifulSoup as bs
import pandas as pd

url = 'https://www.flipkart.com/samsung-mobile-store?otracker=nmenu_sub_Electronics_0_Samsung'
r = requests.get(url)
soup = bs(r.content, 'lxml')

products = soup.select('._3liAhj')
names = []
links = []
ratings = []
for product in products:
     names.append(product.select_one('._2cLu-l').text)
     links.append('https://www.flipkart.com' + product.select_one('._2cLu-l')['href'])
     ratings.append(product.select_one('.hGSR34').text if product.select_one('.hGSR34') is not None else 'No rating')

df = pd.DataFrame(list(zip(names, links, ratings)), columns = ['Name', 'Link', 'Rating'])
print(df)