我正在寻找一种生成布尔值的好方法,该布尔值最终将在过滤器方法的回调函数中使用&&运算符加入。
我试图遍历过滤条件,但是找不到将每个迭代结果合并为以下格式的方法:
return Boolean && Boolean && Boolean && Boolean && Boolean
因为+ = &&布尔值不起作用。
这是我所拥有的并且正在起作用:
//data I am filtering
this.preSearch = [
["The Lord of the Rings", "J. R. R. Tolkien", "English", "1955", "150 milionów"],
["Le Petit Prince (The Little Prince)", "Antoine de Saint-Exupéry", "French", "1943", "140 milionów"],
["Harry Potter and the Philosopher's Stone", "J. K. Rowling", "English", "1997", "120 milionów"],
["The Hobbit", "J. R. R. Tolkien", "English", "1937", "100 milionów"],
["And Then There Were None", "Agatha Christie", "English", "1939", "100 milionów"],
["Dream of the Red Chamber", "Cao Xueqin", "Chinese", "1791", "100 milionów"]
]
//filters, that are set dynamically but let's pretend they are equal to
var filters = ["", "", "english", "19", "1"]
var searchdata = this.preSearch.filter(row => {
return
row[0].toLowerCase().indexOf(filters[0].toLowerCase()) > -1
&& row[1].toLowerCase().indexOf(filters[1].toLowerCase()) > -1
&& row[2].toLowerCase().indexOf(filters[2].toLowerCase()) > -1
&& row[3].toLowerCase().indexOf(filters[3].toLowerCase()) > -1
&& row[4].toLowerCase().indexOf(filters[4].toLowerCase()) > -1
})
我需要可扩展且更优雅的解决方案,因此,如果我增强了过滤后的数组,则不必再用&&添加一行。
答案 0 :(得分:4)
您可以将Array#every
用于过滤器数组。
为了更快地进行检查,您可以预先将过滤器值转换为小写。
var preSearch = [["The Lord of the Rings", "J. R. R. Tolkien", "English", "1955", "150 milionów"], ["Le Petit Prince (The Little Prince)", "Antoine de Saint-Exupéry", "French", "1943", "140 milionów"], ["Harry Potter and the Philosopher's Stone", "J. K. Rowling", "English", "1997", "120 milionów"], ["The Hobbit", "J. R. R. Tolkien", "English", "1937", "100 milionów"], ["And Then There Were None", "Agatha Christie", "English", "1939", "100 milionów"], ["Dream of the Red Chamber", "Cao Xueqin", "Chinese", "1791", "100 milionów"]],
filters = ["", "", "english", "19", "1"].map(s => s.toLowerCase()),
result = preSearch
.filter(row => filters.every((v, i) => row[i].toLowerCase().includes(v)));
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
答案 1 :(得分:1)
您可以这样应用Array.every()
和String.includes()
来做到这一点:
var searchdata = this.preSearch.filter(row => {
// this only returns true if our condition works for
// index = 0, 1, 2, 3, 4
return [0, 1, 2, 3, 4].every(index => {
const rowContent = row[index].toLowerCase();
const filterContent = filters[index].toLowerCase();
// String.includes() is nicer than String.indexOf() here because
// you don't need the ugly -1
return rowContent.includes(filterContent);
});
});