在mysql数据库中，我修改了“ leave”表：
+--------+---------+---------+-------------+---------+--------------------------
|ID_LEAVE|ID_WORKER| FNAME | LNAME | BEGIN_DATE | END_DATE |
+--------+---------+---------+---------+------------+--------------------+------
| 1 | 4 | LEON | SPEED |2019-03-22 07:00:00 |2019-03-23 15:00:00 |
+--------+---------+---------+-------------+---------+--------------------------
“工人表”
+----------+---------+---------+
|ID_WORKER | FNAME | LNAME |
+----------+---------+----------
| 4 | LEON | SPEED |
| 6 | JACK | FAR |
+----------+---------+---------+
“订单”表：
+----------+--------------+---------------+
|ID_ORDER | DESC_ORDER | NUMBER_ORDER |
+----------+--------------+---------------+
| 20 | TEST | TEST |
+----------+--------------+---------------+
“订单状态”表：
+----------+---------+---------+---------------------+-------------------+------------+
| Id_status|ID_WORKER| ID_ORDER| BEGIN_DATE | END_DATE | ORDER_DONE |
+----------+---------+---------+----------+------------+---------+--------------------+
| 30 | 4 | 20 |2019-03-18 06:50:35 |2019-03-18 15:21:32| NO |
| 31 | 4 | 20 |2019-03-20 06:44:12 |2019-03-20 15:11:23| NO |
| 32 | 4 | 20 |2019-03-22 06:50:20 |2019-03-22 12:22:33| YES |
| 33 | 6 | 20 |2019-03-18 06:45:11 |2019-03-18 15:14:45| NO |
| 34 | 6 | 20 |2019-03-20 06:50:22 |2019-03-20 15:10:32| NO |
| 35 | 6 | 20 |2019-03-22 06:54:11 |2019-03-22 11:23:45| YES |
+----------+---------+---------+------------+---------+-------------------+-----------+
我做了什么：
我可以在订单上总结每个工人的“订单时间”（在order_status表中），包括从假表中总结“休假时间”并总结“订单时间” +“休假时间”。我也已正确选择了彼此的工人订单（LNAME，FNAME）订单（DESC_ORDER和NUMBER_ORDER）和“ TOTAL TIME”。我在下面编写了mysql命令：
SELECT workers.FNAME,
workers.LNAME,
order_statusAgg.NUMBER_ORDER,
order_statusAgg.DESC_ORDER,
SEC_TO_TIME(SUM(order_statusAgg.stime)) AS 'ORDER TIME',
IFNULL(SEC_TO_TIME(SUM(leaveAgg.ltime)),'00:00:00') AS 'LEAVE TIME',
ADDTIME(SEC_TO_TIME(SUM(order_statusAgg.stime)), IFNULL(SEC_TO_TIME(SUM(leaveAgg.ltime)), '00:00:00')) AS 'TOTAL TIME'
FROM workers
LEFT JOIN (SELECT leave.ID_WORKER, SUM((datediff(leave.BEGIN_DATE, leave.END_DATE) + 1) * (time_to_sec(time(leave.END_DATE)) - time_to_sec(time(leave.BEGIN_DATE)))) AS ltime FROM leave
LEFT JOIN
(SELECT ID_WORKER, MIN(BEGIN_DATE) AS 'MIN_BEGIN_DATE', MAX(END_DATE) AS 'MAX_END_DATE'
FROM order_status GROUP BY ID_WORKER) ordstat ON
leave.ID_WORKER = ordstat.ID_WORKER
WHERE leave.END_DATE <= MAX_END_DATE AND leave.BEGIN_DATE >= MIN_BEGIN_DATE GROUP BY leave.ID_WORKER) leaveAgg
ON leaveAgg.ID_WORKER = workers.ID_WORKER
LEFT JOIN (
SELECT order_status.ID_WORKER, orders.NUMBER_ORDER, orders.DESC_ORDER,
SUM((TIME_TO_SEC(order_status.END_DATE) - TIME_TO_SEC(order_status.BEGIN_DATE))) AS stime
FROM order_status INNER JOIN orders
ON orders.ID_ORDER = order_status.ID_ORDER
GROUP BY order_status.ID_WORKER) order_statusAgg
ON workers.ID_WORKER = order_statusAgg.ID_WORKER
WHERE order_statusAgg.NUMBER_ORDER LIKE 'TEST'
GROUP BY workers.ID_WORKER;
但是在那之后出了点问题：
+---------+---------+---------------+------------+------------+--------------+-----------+
| FNAME | LNAME | NUMBER_ORDER | DESC_ORDER | ORDER TIME | LEAVE_TIME | TOTAL TIME|
+---------+---------+---------------+------------+------------+--------------+-----------+
| LEON | SPEED | TEST | TEST | 22:30:21 | 00:00:00 | 22:30:21 |
+---------+---------+---------------+------------+------------+--------------+-----------+
| JACK | FAR | TEST | TEST | 21:19:18 | 00:00:00 | 21:19:18 |
+---------+---------+---------------+------------+------------+--------------+-----------+
为什么Leon Speed的“ Leave_time”设置为00：00：00，尽管他在以下时间有离开时间： 从2019-03-22 07:00:00到2019-03-23 15:00:00。
对我来说应该有所不同：
+---------+---------+---------------+------------+------------+--------------+-----------+
| FNAME | LNAME | NUMBER_ORDER | DESC_ORDER | ORDER TIME | LEAVE_TIME | TOTAL TIME|
+---------+---------+---------------+------------+------------+--------------+-----------+
| LEON | SPEED | TEST | TEST | 22:30:21 | 08:00:00 | 30:30:21 |
+---------+---------+---------------+------------+------------+--------------+-----------+
| JACK | FAR | TEST | TEST | 21:19:18 | 00:00:00 | 21:19:18 |
+---------+---------+---------------+------------+------------+--------------+-----------+
因为订单于22-03-2019结束（尽管他已从22-03-2019离开至23-03-2019）。 与下面的代码行有关吗？
LEFT JOIN (SELECT leave.ID_WORKER, SUM((datediff(leave.BEGIN_DATE, leave.END_DATE) + 1) * (time_to_sec(time(leave.END_DATE)) - time_to_sec(time(leave.BEGIN_DATE)))) AS ltime FROM leave
LEFT JOIN
(SELECT ID_WORKER, MIN(BEGIN_DATE) AS 'MIN_BEGIN_DATE', MAX(END_DATE) AS 'MAX_END_DATE'
FROM order_status GROUP BY ID_WORKER) ordstat ON
leave.ID_WORKER = ordstat.ID_WORKER
WHERE leave.END_DATE <= MAX_END_DATE AND leave.BEGIN_DATE >= MIN_BEGIN_DATE GROUP BY leave.ID_WORKER) leaveAgg
ON leaveAgg.ID_WORKER = workers.ID_WORKER
我需要如何处理的帮助。我不是一个懒惰的人，但我也不是Mysql专家（因为我正在训练3个星期）。有人可以提供建议或想法吗？预先感谢您的任何建议。