从具有条件的多个词典中获取多个数据

Question

我有多个词典，我想获取日期最早的分支的“最早的日期”和“名称”

我可以使用此日期获取最旧的日期，但是无法获取哪个分支具有最旧的日期。

x = datetime.datetime.now()

# objects


branch_1 = {
    "name": "b1",
    "gps": (48.8946865, 2.3622423),
    "oldestDate": dt.datetime(2019, 1, 7),
}

branch_2 = {
    "name": "b2",
    "gps": (48.839955, 2.288605),
    "cars": 7,
    "oldestDate": dt.datetime(2016, 1, 17),
}

branch_3 = {
    "name": "b3",
    "gps": (48.844244, 2.401435),
    "oldestDate": dt.datetime(2019, 1, 21),

}

listOBranches = [branch_1, branch_2, branch_3]
mtlst2 = []


def branchPriorityScore(listOBranches):
    for item in listOBranches:
        score = x - (item["oldestDate"])
        mtlst2.append(score)
        dateMax2 = np.max(mtlst2)
        name = item["name"]

    # return mtlst2
    print("Maximum Priority Branch : ", dateMax2)  # correct score
    # print("Maximum Priority Branch : ", np.max(mtlst2(item["name"])), dateMax2)


# mtlst2

branchPriorityScore(listOBranches)

Answer 1

我会这样做的。

def branchPriorityScore(listOBranches):
    oldest = datetime.timedelta()
    i = 0 #if you need index
    for index,item in enumerate(listOBranches):
        score = x - (item["oldestDate"])
        if score > oldest:
            oldest = score
            i = index #if you need index
            name = item["name"]


    print (name,i,oldest,listOBranches[i]['oldestDate'])

不确定为什么需要mtlst2，但也可以在循环中添加它。