如何根据特定条件选择记录

Question

我有一个名为“ ticket_lc”的表，如下图所示

从上表中，我只需要选择满足条件的记录

条件：票证状态应为“已分配”，“已关闭”和“已解决”

因此，在上表中，只有102张票证满足该条件，如果票证包含这3张票证之外的其他票证，则我的查询不应选择这些票证。

有人可以帮我吗.. !!!

谢谢

Answer 1

您可以进行聚合：

select ticket_id
from table t
group by ticket_id
having sum( case when status not in ('assigned', 'closed', 'resolved') then 1 else 0 end ) = 0 and
       count(*) = 3;

如果您的票证状态重复，请在distinct内使用count()。

Answer 2

以下是用于BigQuery标准SQL

#standardSQL
SELECT ticket_id
FROM `project.dataset.ticket_lc`
GROUP BY ticket_id
HAVING COUNT(DISTINCT status) = 3
AND COUNTIF(LOWER(status) NOT IN ('assigned', 'closed', 'resolved')) = 0 

Yo可以使用问题中的示例数据来测试，玩游戏，如下例所示

#standardSQL
WITH `project.dataset.ticket_lc` AS (
  SELECT 101 ticket_id, 'Assigned' status UNION ALL
  SELECT 101, 'Pending' UNION ALL
  SELECT 101, 'Resolved' UNION ALL
  SELECT 101, 'Closed' UNION ALL
  SELECT 102, 'Assigned' UNION ALL
  SELECT 102, 'Resolved' UNION ALL
  SELECT 102, 'Closed' UNION ALL
  SELECT 103, 'Assigned' UNION ALL
  SELECT 103, 'Pending' UNION ALL
  SELECT 103, 'Pending' UNION ALL
  SELECT 103, 'Assigned' UNION ALL
  SELECT 103, 'Resolved' UNION ALL
  SELECT 103, 'Closed' 
)
SELECT ticket_id
FROM `project.dataset.ticket_lc`
GROUP BY ticket_id
HAVING COUNT(DISTINCT status) = 3
AND COUNTIF( LOWER(status) NOT IN ('assigned', 'closed', 'resolved')) = 0 

有结果

Row ticket_id    
1   102  

Answer 3

一个有趣的问题。我想出了这个检查，是否涵盖了所有内容并且金额是否正确：

WITH t AS (SELECT * FROM UNNEST(
  [struct(101 as ticket_id, 'assigned' as status),(101,'closed'),
    (102,'assigned'),(102,'resolved'),(102,'closed'),
    (104,'assigned'),(104,'assigned'),(104,'closed'),
    (103,'assigned'),(103,'pending'),(103,'pending'),(103,'assigned'),(103,'resolved'),(103,'closed')]  
  )
)

SELECT ticket_id, array_agg(distinct status) as st 
FROM t
group by 1
having (SELECT count(1)=3 FROM unnest(st) a left join unnest(['assigned','resolved','closed']) b on a=b)

包括调整后的样本数据以涵盖更多问题案例。