Question

我有这个数组：

array:2 [▼
  0 => array:3 [▼
    "time" => 7780
    "name" => "John A. Doe"
    "photo" => "johndoe.png"
  ]
  1 => array:3 [▼
    "time" => 49800
    "name" => "Jane B. Doe"
    "photo" => "janedoe.png"
  ]
]

time的值是秒，我的问题是如何遍历数组，以便可以运行类似以下的函数：

"time" => $this->secondsToHumanReadable(49800)

我的函数secondsToHumanReadable已通过测试并且可以正常工作，我只希望它插入数组结果内的time值。

更新：

所需的输出将是：

array:2 [▼
      0 => array:3 [▼
        "time" => '2 days, 1 hour, 3 minutes, 45 seconds'
        "name" => "John A. Doe"
        "photo" => "johndoe.png"
      ]
      1 => array:3 [▼
        "time" => '3 hour, 15 minutes, 20 seconds'
        "name" => "Jane B. Doe"
        "photo" => "janedoe.png"
      ]
    ]

Answer 1

使用array_map()

$new_array = array_map(function($item) use ($this) {
  $item['time'] = $this->secondsToHumanReadable($item['time']);
  return $item;
}, $my_array);

使用array_map()的好处是返回的数组是一个新数组，因此您无需更改初始数组。通常最好不要更改数据结构

Answer 2

您可以使用foreach，如@u_mulder所说。


// Copying the original array
$result = $array;

foreach($result as $item) {
    $item["time"] = $this->secondsToHumanReadable($item["time"]);
}

print_r($result);

Answer 3

您可以使用someMethod(new Bar()); // I want something similar to this that compiles, Bar adheres to Foo someMethod(new Bar2()); // I'd like to have a compile-time error, Bar2 doesn't adhere to Foo，但可以使用references：

foreach

输出

$data = [
  [
    'time' => time()
  ],

  [
    'time' => time() - 5000
  ]
];

foreach ($data as &$datum) {  
  $datum['time'] = date('d/m/Y', $datum['time']);
}

print_r($data);

实时示例

Repl

Answer 4

您可以尝试

array(
  "time" => function($foo){return $foo;},
    "name" => "John A. Doe",
    "photo" => "johndoe.png"
);

PHP-对数组值执行函数

4 个答案: