Question

我已经建立了ICollection<User>列表：

public ICollection<User> MyUsers { get; set; }
public IList<User> GetUserList(string path)
{
        MyUsers = File.ReadAllLines(path)
           .Where(linia => linia.Length > 1)
           .Select(line => Parse(line))
           .ToList();            

        return new List<User>(MyUsers);
}

private static User Parse(string line)
{
        var column = line.Split('|');

        return new User
        {
            ReadTime = column [0],
            idUser = column [1],
            LastName = column [2],
            FirstName = column [3],
            City = column[4]
        };
}

我的源文本文件如下所示：

2019-03-03|1|LN1|FN1|Berlin
2019-03-03|2|LN2|FN2|Rome
2019-03-03|3|LN3|FN3|Wien
2019-03-03|4|LN4|FN4|Londyn
....
2019-03-27|1|LN1|FN1|Berlin
2019-03-27|2|LN2|FN2|Rome
2019-03-27|3|LN3|FN3|Wien
2019-03-27|4|LN4|FN4|Londyn

运行此命令时，将获得具有相同记录的列表，只有ReadTime是不同的。

如何设置唯一 MyUsers列表，其中ReadTime列将在最后日期出现？

Answer 1

您可以尝试使用简单的GroupBy方法：

  MyUsers = File.ReadAllLines(path)
    .Where(linia => linia.Length > 1)
    .Select(line => Parse(line))
    .GroupBy(
      u => u.idUser, 
      (key, grp) => new User() {
        ReadTime = grp.Select(u => u.ReadTime).Max(),
        idUser = key,
        LastName = grp.Select(u => u.LastName).FirstOrDefault(),
        FirstName = grp.Select(u => u.FirstName).FirstOrDefault(),
        City = grp.Select(u => u.City).FirstOrDefault(),
      })
    .ToList();

Answer 2

您可以使用MoreLINQ-NuGet-package，有有用的DistinctBy功能：

MyUsers = File.ReadAllLines(path)
    .Where(linia => linia.Length > 1)
    .Select(line => Parse(line))
    .OrderByDescending(r => r.ReadTime)
    .DistinctBy(r => new { r.City, r.FirstName, r.idUser, r.LastName })
    .ToList();

Answer 3

我们可以GroupBy并找到每个组的Max日期：

   IEnumerable<string> result = File
     .ReadLines(path)    
     .Where(line => !string.IsNullOrWhiteSpace(line)) // to be on the safe side
     .Select(line => {
        int p = line.IndexOf('|');

        return new {
          date = line.Substring(0, p), // date to take Max
          key = line.Substring(p + 1)  // group key
        };
      })
     .GroupBy(item => item.key, item => item.date)
     .Select(chunk => string.Join("|", chunk.Key, chunk.Max(item => item)));

过滤掉重复项后，我们可以将其解析为一个集合：

   MyUsers = result
     .Select(line => Parse(line))
     .ToList();

使用LINQ从文本文件中获取唯一记录

3 个答案: