Question

我正在使用Django处理一个项目，我动态创建了一个输入字段并尝试提交它，但是我却没有这样做，我在网上搜索了一下，发现可以用formset_factory完成，但是当我尝试使用它时，我收到此错误

CatName = int(float(request.POST.get('CatName')))
TypeError: float() argument must be a string or a number, not 'NoneType'

这是我的代码

form.html

<form action="." method="post" id="PostCat__form">{% csrf_token %}
                <input type="hidden" name="deyHidden" value="category_hidden">
                {% comment %} {{ catForm | crispy }}       
                <input type="hidden" name="deyHidden" value="category_hidden"> {% endcomment %}
                <input type="text" class="form-control" name="CatName[]" >
                <input type="text" class="form-control" name="CatName[]" >
                <input type="text" class="form-control" name="CatName[]" >
                <input type="text" class="form-control" name="CatName[]" >

                <div class="form-group">
                    <h6 id="PostCat__show"></h6>
                    <img src=" {% static 'images/ajax-loader.gif' %}" style="Display:none;" id="PostCat__img">
                    <button class="btn btn-outline-info" type="submit"   id="PostCat__submit">Create</button>
                </div>
            </form>

model.py

class Category(models.Model):
    CatName = models.CharField(max_length=100)

view.py

        myFormCat = CatPostForm(request.POST)
        CatName = int(float(request.POST.get('CatName')))
        # print(CatName)
        formset = formset_factory(FormsetForm, CatName=CatName)(request.POST)

        if myFormCat.is_valid() and formset.is_valid():
            for form_c in formset:
                if not form_c.cleaned_data['CatName']:
                    Category.objects.get_or_create(CatName=CatName)
                    response_data = {
                        'SType': 'success',
                        'message': "Saved Successfully"
                    }                
        return HttpResponse(json.dumps(response_data), content_type="application/json")

forms.py

class CatPostForm(forms.ModelForm):
    class Meta: 
        model=Category
        fields = ['CatName']

请问我该怎么做，这样我才能成功提交表单

Answer 1

在您的views.py

from django.forms import formset_factory
CatPostFormSet = formset_factory(CatPostForm)
catformset = CatPostFormSet() #this goes to your page context. do the validations here also after the post

在您的form.html

<form method="post">
    {{ formset.management_form }}
        {{formset}}
</form>

在Django中提交动态创建的输入字段

1 个答案: