如何基于Impala查询中的调整查找值的总和

时间:2019-03-27 11:48:21

标签: hive hiveql impala

我有一个名为REV的Impala表,其中包含每个电汇代码的wire_code,金额和报告行。

+---------+------+----------------+
|wire_code| amt  | Reporting_line |
+---------+------+----------------+
| abc     | 100  | Database       |
+---------+------+----------------+
| abc     | 10   | Revenue        |
+---------+------+----------------+
| def     | 50   | Database       |
+---------+------+----------------+
| def     | 25   | Polland        |
+---------+------+----------------+
| ghi     | 250  | Cost           |
+---------+------+----------------+
| jkl     | 300  | Cost           |
+---------+------+----------------+

and the other table is FA which is having wire_code and Ajusted_wire_code    

    +---------+------+
    |wire_code|adj_wc|
    +---------+------+
    | abc     | def  |
    +---------+------+
    |  ghi    | jkl  |
    +---------+------+


I need to adjust the amount of wire code which is available as adj_wc in FA table.
For example:

FA表中有“ abc”,并且将其调整为“ def”,然后我的输出应该是-wire_code“ def”的数量如下(abc和def),而“ abc”数量将保持不变。

我正在使用下面提供的查询,它正在删除两种电汇代码中都不常见的记录,例如,报告行Polland的def。并且abc有一个额外的报告行收入,当abc移至def时,需要将其添加到def电汇代码中。

abc正在调整为def-abc中不存在的def报告行将保持不变,并且将调整公共报告行。

  select r.wire_code, r.amt+coalesce(a.amt,0) as amt
      from REV r
           left outer join FA f on r.wire_code=f.adj_wc     --adjustments
           left outer join REV a on f.wire_code=a.wire_code --adjusted amount
         Where REP.REPORTING_LINE = REP1.REPORTING_LINE
    ;

预期结果:

+---------+------+----------------+
|wire_code| amt  | Reporting_line |
+---------+------+----------------+
| abc     | 100  | Database       |
+---------+------+----------------+
| abc     | 10   | Revenue        |
+---------+------+----------------+
| def     | 150  | Database       |
+---------+------+----------------+
| def     | 10   | Revenue        |
+---------+------+----------------+
| def     | 25   | Polland        |
+---------+------+----------------+
| ghi     | 250  | Cost           |
+---------+------+----------------+
| jkl     | 550  | Cost           |
+---------+------+----------------+

1 个答案:

答案 0 :(得分:0)

我认为下面的查询在蜂巢中工作

尝试黑斑羚,让我知道

create table rev
(
wire_code varchar(200),
amt   int,
reporting varchar(200)
);

insert into rev values ('abc',100,'Database');
insert into rev values ('abc',10,'Revenue');
insert into rev values ('def',50,'Database');
insert into rev values ('def',25,'Polland');
insert into rev values ('ghi',250,'cost');
insert into rev values ('jkl',300,'cost');

create table fa
(
wire_code varchar(200),
adj_wc varchar(200)
);

insert into fa values ('abc','def');
insert into fa values ('ghi','jkl');

select rev.wire_code,
case when rev.wire_code=adj_wc then sum(amt) over(partition by reporting)
else amt end as amt,reporting
from rev inner join fa 
on (rev.wire_code=fa.wire_code or rev.wire_code=fa.adj_wc)
order by 1