Question

我正在尝试将XML文件转换为CSV文件。（基本上是将数据从XML转换为表格格式），但是对于该特定XML文件，我需要XSL文件进行csv转换。这是一个复杂的XML。

我需要CSV格式的XML下面的所有字段。这是示例XML文件。我需要提取所有相关字段

2018-11-05T16：30：42.220Z 2018-11-05T16：30：43.007Z 2018-11-05T16：30：46.151Z 2018-11-05T16：30：45.366Z

import java.io.File;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.transform.Result;
import javax.xml.transform.Source;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;

import org.w3c.dom.Document;

public class Temp {

    public static void main(String args[]) throws Exception {

        Document document;

        File stylesheet = new File("C:/Users/mmahajan/Desktop/Input/style.xsl");
        File xmlSource = new File("C:/Users/mmahajan/Desktop/Input/subject-beataml-BAML-S8 AST-FLT3-20190325114820225683361888824.xml");

        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        DocumentBuilder builder;
        try {
            builder = factory.newDocumentBuilder();
            document = builder.parse(xmlSource);
            StreamSource stylesource = new StreamSource(stylesheet);
            Transformer transformer = TransformerFactory.newInstance().newTransformer(stylesource);
            Source source = new DOMSource(document);
            Result outputTarget = new StreamResult(new File("C:/Users/mmahajan/Desktop/Input/x.csv"));
            transformer.transform(source, outputTarget);

        } catch (ParserConfigurationException e) {
            e.printStackTrace();
        }

    }

}

这是示例XSL文件。

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" >
<xsl:output method="text" omit-xml-declaration="yes" indent="no"/>
<xsl:template match="/">
Metaversion,StudyOID,SubjectKey,CreationDateTime,VisitDate,NotDone,Branch,Name,StudyEventOID,Name,Started,FormOID,ItemGroupOID,TimezoneOffset,Value,EntryType,FieldName,ItemOID,UserOID,DateTimeStamp
<xsl:for-each select="//AuditRecord">
<xsl:value-of select="concat(//ClinicalData/@MetaDataVersionOID,',',//ClinicalData/@StudyOID,',',//ClinicalData/SubjectData/@SubjectKey,',',//ClinicalData/SubjectData/StudyEventData/@CreationDateTime,',',//ClinicalData/SubjectData/StudyEventData/@CreationDateTime,',',//ClinicalData/SubjectData/StudyEventData/@VisitDate,',',//ClinicalData/SubjectData/StudyEventData/@NotDone,',',//ClinicalData/SubjectData/StudyEventData/@Branch,',',//ClinicalData/SubjectData/StudyEventData/@Name,',',//ClinicalData/SubjectData/StudyEventData/@StudyEventOID,',',//ClinicalData/SubjectData/StudyEventData/FormData/',',//ClinicalData/SubjectData/StudyEventData/FormData/@Started,',',//ClinicalData/SubjectData/StudyEventData/FormData/@FormOID,',',//ClinicalData/SubjectData/StudyEventData/FormData/ItemGroupData/@ItemGroupOID,',',//ClinicalData/SubjectData/StudyEventData/FormData/ItemGroupData/ItemData/@TimezoneOffset,',',//ClinicalData/SubjectData/StudyEventData/FormData/ItemGroupData/ItemData/@Value,',',//ClinicalData/SubjectData/StudyEventData/FormData/ItemGroupData/ItemData/@EntryType,',',//ClinicalData/SubjectData/StudyEventData/FormData/ItemGroupData/ItemData/@FieldName,',',//ClinicalData/SubjectData/StudyEventData/FormData/ItemGroupData/ItemData/@ItemOID,',',//ClinicalData/SubjectData/StudyEventData/FormData/ItemGroupData/ItemData/AuditRecord/UserRef/@UserOID,',',//ClinicalData/SubjectData/StudyEventData/FormData/ItemGroupData/ItemData/AuditRecord/UserRef/@DateTimeStamp,
'&#xA;')"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>

我们如何将XSL转换为XML格式？

0 个答案: