Question

我有一个商品表和一个评论表。
我想编写一个查询以返回每种产品的评论的COUNT和AVG。
AND ，如果没有评论，我希望它为COUNT和AVG返回0 / null。

产品表

+--------+----------+
| prodId | prodName |
+--------+----------+
|   1    |  apple   |
|   2    |  banana  |
|   3    |  cacao   |
+--------+----------+

查看表

+----------+----------+--------+
| reviewId |  prodId  | rating |
+----------+----------+--------+
|    1     |     1    |    1   |
|    2     |     1    |    1   |
|    3     |     2    |    5   |
|    4     |     2    |    5   |
+----------+----------+--------+

这就是我想要的结果：

+--------+----------+--------+-------+
| prodId | prodName |   avg  | count |
+--------+----------+--------+-------+
|   1    |  apple   |    1   |   2   |
|   2    |  banana  |    5   |   2   |
|   3    |  cacao   |   null |   0   |
+--------+----------+--------+-------+

我能够获得带有评论的产品的COUNT和AVG

SELECT p.prodid, p.prodname, avg(r.stars), count(r.productid)
FROM products p 
INNER JOIN reviews r ON p.productid=r.productid 
GROUP BY p.productid

+--------+----------+--------+-------+
| prodId | prodName |   avg  | count |
+--------+----------+--------+-------+
|   1    |  apple   |    1   |   2   |
|   2    |  banana  |    5   |   2   |
+--------+----------+--------+-------+

对于没有评论的产品，我也可以获得COUNT和AVG

SELECT p.prodid, p.prodname, avg(r.stars), count(r.stars)
FROM products p
LEFT OUTER JOIN reviews r 
ON (p.productid=r.productid) WHERE r.productid IS NULL
GROUP BY p.productid

+--------+----------+--------+-------+
| prodId | prodName |   avg  | count |
+--------+----------+--------+-------+
|   3    |  cacao   |   null |   0   |
+--------+----------+--------+-------+

但是我不知道MySql是否可以查询和计数匹配的结果并计算一次查询中不匹配的结果。

Answer 1

只需从第二个查询中删除where condition

SELECT p.prodid, p.prodname, avg(r.stars), count(r.stars)
FROM products p
LEFT OUTER JOIN reviews r 
ON p.productid=r.productid
GROUP BY p.productid,p.prodname

Answer 2

在MySQL中，“ LEFT JOIN”实际上与LEFT OUTER JOIN相同。 OUTER关键字是可选的。要获得结果，您只需要执行简单的“ LEFT JOIN”并按ID（或任何其他唯一键）进行分组：

SELECT 
    `p`.`prodId` AS `ID`, 
    `p`.`prodName` AS `Product`, 
    avg(`r`.`rating`) AS `AVG Rating`, 
    count(`r`.`reviewId`) AS `Vote Count`
FROM `products` AS `p`
LEFT JOIN `reviews` AS `r` ON `p`.`prodId` = `r`.`prodId`
GROUP BY `p`.`prodId`

如何在联接表上查询COUNT并返回计数均为0且计数> 0的记录

2 个答案: