数据帧中特定列的乘法，而Pattren不变

Question

我有两个数据帧，即share和Log_Returns。我想将份额的第一位数乘以Log_Returns的第一列。第二列的第二位数，依此类推。

shares
           0
0   0.319297
1  99.680703

Log_return

       HIGH       MID
0 -1.998061 -1.991331
1 -0.014573 -1.981635
2 -2.015117 -1.978619
3  0.028488 -2.000455

我尝试了以下代码，但获得了串行输出。

for j in range(Log_return.shape[1]):
            i = j
            for k in range(len(Log_return)):
                print(shares.iloc[i, 0] * Log_return.iloc[k, j])


-0.6379746350243671
-0.004652966683445539
-0.6434205307519527
0.009096189190505598
-198.49724749816215
-197.53080296760479
-197.23014837824016
-199.40677745293362

I want someone to help me for finding this results.
Log_return

       HIGH         MID
B -0.637975 -198.497247
C -0.004653 -197.530803
D -0.643421 -197.230148
E  0.009096 -199.406777

Answer 1

使用numpy：

import numpy as np

np.multiply(log_return, shares.T)

应提供所需的输出。