Question

我有一个关联数组，我需要合并具有相同日期的对应key =>值对

Array
(
    [0] => Array
        (
            [CreatedDate] => 2019-03-20
            [Whreceived] => 1
        )

    [1] => Array
        (
            [CreatedDate] => 2019-02-24
            [Whreceived] => 1
        )

    [2] => Array
        (
            [CreatedDate] => 2019-03-21
            [Whreceived] => 1
        )

    [3] => Array
        (
            [CreatedDate] => 2019-03-20
            [InProcess] => 1
        )

    [4] => Array
        (
            [CreatedDate] => 2019-03-19
            [InProcess] => 1
        )

    [5] => Array
        (
            [CreatedDate] => 2019-03-25
            [OnHold] => 2
        )

    [6] => Array
        (
            [CreatedDate] => 2019-03-19
            [WhInwardDone] => 1
        )

)

预期产量

Array
(
    [0] => Array
        (
            [CreatedDate] => 2019-03-20
            [Whreceived] => 1
            [InProcess] => 1

        )

    [1] => Array
        (
            [CreatedDate] => 2019-02-24
            [Whreceived] => 1
        )

    [2] => Array
        (
            [CreatedDate] => 2019-03-21
            [Whreceived] => 1
        )



    [4] => Array
        (
            [CreatedDate] => 2019-03-19
            [InProcess] => 1
            [WhInwardDone] => 1

        )

    [5] => Array
        (
            [CreatedDate] => 2019-03-25
            [OnHold] => 2
        )



)

基本上，我需要具有唯一日期及其所有对应值的单个数组

Answer 1

您可以使用$merged_array = array_reduce($array, function ($c, $v) { if (($k = array_search($v['CreatedDate'], array_column($c, 'CreatedDate'))) !== false) { $c[$k] = array_merge($c[$k], $v); } else { $c[] = $v; } return $c; }, array()); print_r($merged_array);进行此操作，检查新数组中是否存在日期，如果存在，将当前值与该值合并，否则在新数组中创建一个新值。

$merged_array = array();
foreach ($array as $v) {
    if (($k = array_search($v['CreatedDate'], array_column($merged_array, 'CreatedDate'))) !== false) {
        $merged_array[$k] = array_merge($merged_array[$k], $v);
    }
    else {
        $merged_array[] = $v;
    }
}

或者您可以使用一个简单的foreach循环：-）

Array
(
    [0] => Array
        (
            [CreatedDate] => 2019-03-20
            [Whreceived] => 1
            [InProcess] => 1
        )
    [1] => Array
        (
            [CreatedDate] => 2019-02-24
            [Whreceived] => 1
        )
    [2] => Array
        (
            [CreatedDate] => 2019-03-21
            [Whreceived] => 1
        )
    [4] => Array
        (
            [CreatedDate] => 2019-03-19
            [InProcess] => 1
            [WhInwardDone] => 1
        )
    [5] => Array
        (
            [CreatedDate] => 2019-03-25
            [OnHold] => 2
        )
)

输出：

Actions -> Modify

research these for yourself

Answer 2

尝试以下Easy Understand trick：

$array_mix = array(
        array("CreatedDate" => "2019-03-20","Whreceived" => 1),
        array("CreatedDate" => "2019-02-24","Whreceived" => 1),
        array("CreatedDate" => "2019-03-21","Whreceived" => 1),
        array("CreatedDate" => "2019-03-20","InProcess" => 1),
        array("CreatedDate" => "2019-03-19","InProcess" => 1),
        array("CreatedDate" => "2019-03-25","OnHold" => 1),
        array("CreatedDate" => "2019-03-19","WhInwardDone" => 1),
    );

使用foreach：

    $Newarray = array();
foreach($array_mix as $key => $array_mix_items){

    if($array_mix_items['Whreceived']){
        $Newarray[$array_mix_items['CreatedDate']]['CreatedDate']   = $array_mix_items['CreatedDate'];
        $Newarray[$array_mix_items['CreatedDate']]['Whreceived']   = $array_mix_items['Whreceived'];
    }
    if($array_mix_items['InProcess']){
        $Newarray[$array_mix_items['CreatedDate']]['CreatedDate']   = $array_mix_items['CreatedDate'];
        $Newarray[$array_mix_items['CreatedDate']]['InProcess']    = $array_mix_items['InProcess'];
    }
    if($array_mix_items['WhInwardDone']){
        $Newarray[$array_mix_items['CreatedDate']]['CreatedDate']   = $array_mix_items['CreatedDate'];
        $Newarray[$array_mix_items['CreatedDate']]['WhInwardDone'] = $array_mix_items['WhInwardDone'];
    }
    if($array_mix_items['OnHold']){
        $Newarray[$array_mix_items['CreatedDate']]['CreatedDate']   = $array_mix_items['CreatedDate'];
        $Newarray[$array_mix_items['CreatedDate']]['OnHold']       = $array_mix_items['OnHold'];
    }
}

输出：

echo "<pre>";
print_r($Newarray);
echo "</pre>";

在pre tag中的输出：

    Array
(
    [2019-03-20] => Array
        (
            [CreatedDate] => 2019-03-20
            [Whreceived] => 1
            [InProcess] => 1
        )

    [2019-02-24] => Array
        (
            [CreatedDate] => 2019-02-24
            [Whreceived] => 1
        )

    [2019-03-21] => Array
        (
            [CreatedDate] => 2019-03-21
            [Whreceived] => 1
        )

    [2019-03-19] => Array
        (
            [CreatedDate] => 2019-03-19
            [InProcess] => 1
            [WhInwardDone] => 1
        )

    [2019-03-25] => Array
        (
            [CreatedDate] => 2019-03-25
            [OnHold] => 1
        )

)

需要合并具有相同键值对的单个数组元素

2 个答案: