我正试图让agrep与seconds匹配second和 not millisecond，但似乎没有costs的任何值即可完成此操作。
我尤其感到困惑的是，deletions / insertions的成本没有价值，似乎可以解决问题-正如我所看到的，second是从{{ 1}}，而seconds是1个删除和5个插入。
（警告millisecond可能需要一段时间...对于lapply和length.out = 10，您会更快地得到相同的结果）
0:10我在这里想念什么？没办法用rng = c(seq(0, 1, length.out = 20), 0:100)
x = expand.grid(insertions = rng, substitutions = rng, deletions = rng)
units = c("millisecond", "second", "minute", "hour", "day",
"week", "month", "quarter", "year")
x$match = lapply(seq_len(nrow(x)), function(ii)
agrep('second', units, value = TRUE, costs = x[ii, ]))
x$match_which = sapply(x$match, paste, collapse = '|')
sort(table(x$match_which))
# millisecond|second|minute|hour|week|month|year
# 57
# millisecond|second|minute|hour|week|month|quarter|year
# 13276
# millisecond|second|month
# 23316
# millisecond|second|minute|month|quarter
# 37842
# millisecond|second|minute|quarter
# 251480
# millisecond|second|minute|hour|day|week|month|quarter|year
# 409865
# millisecond|second
# 1035725
完成我的任务（将seconds与second而不是millisecond匹配）吗？