找到最低的测试分数和两个高分的平均值

时间:2019-03-27 03:10:42

标签: python average display

我在作业中发现了其他所有内容,但我坚持到最后一步,要求我找到最低的测试分数,然后显示最高的两个测试分数的平均值,也显示最低的分数。我知道我需要在“ def findAndReturnLowest”下面添加一个if / elif / else函数,但出现错误。这是我应该做的屏幕截图enter image description here

这是我的代码

def main():
    score1 = 0.0
    score2 = 0.0
    score3 = 0.0

    score1 = getTestScore()
    score2 = getTestScore()
    score3 = getTestScore()

    calcAvgAndDisplayResults(score1, score2, score3)

def calcAvgAndDisplayResults(s1, s2, s3):
    lowest = 0.0
    average = 0.0
    lowest = findAndReturnLowest(s1, s2, s3)
def findAndReturnLowest(s1, s2, s3):


    average = (s1+s2+s3-lowest)/2
    print("Average = ", average)

def getTestScore():
    test = 0.0
    test=float(input("Enter a test score between 0 and 100: "))
    return test

# start of program
main()

2 个答案:

答案 0 :(得分:1)

使用嵌套的def findAndReturnLowest(s1, s2, s3): if s1 > s3 and s2 > s3: return s3 else: return s2 if s1 > s2 else s1

{{1}}

答案 1 :(得分:0)

应该可以使用的非常简单的方法,但是有很多方法:

def main():
    score1 = 0.0
    score2 = 0.0
    score3 = 0.0

    score1 = getTestScore()
    score2 = getTestScore()
    score3 = getTestScore()

    calcAvgAndDisplayResults(score1, score2, score3)

def calcAvgAndDisplayResults(s1, s2, s3):
    lowest = findAndReturnLowest(s1, s2, s3)

def findAndReturnLowest(s1, s2, s3 ):
    lowest = min([int(x) for x in [s1,s2,s3]])
    average = (s1+s2+s3-lowest)/2
    print("Average = ", average)
    print("Lowest = ", lowest)

def getTestScore():
    test = 0.0
    test=float(input("Enter a test score between 0 and 100: "))
    return test

# start of program
main()