我正在使用Flutter。我有一个带有3个标签的简单应用。每个选项卡中都有一个带有ListView的RefreshIndicator。这些行是用另一种方法构建的。这是代码:
@override
Widget build(BuildContext context) {
final GlobalKey<RefreshIndicatorState> _RIKey1 = new GlobalKey<RefreshIndicatorState>();
final GlobalKey<RefreshIndicatorState> _RIKey2 = new GlobalKey<RefreshIndicatorState>();
final GlobalKey<RefreshIndicatorState> _RIKey3 = new GlobalKey<RefreshIndicatorState>();
debugPrint(_RIKey1.toString());
debugPrint(_RIKey2.toString());
debugPrint(_RIKey3.toString());
return new Scaffold(
body: new DefaultTabController(
length: 3,
child: new Scaffold(
appBar: new AppBar(
actions: <Widget>[
IconButton(
icon: Icon(Icons.refresh),
onPressed: () {
_RIKey1.currentState.show();
},
)
],
bottom: new TabBar(
tabs: [
new Tab(icon: new Icon(Icons.view_list)),
new Tab(icon: new Icon(Icons.hotel)),
new Tab(icon: new Icon(Icons.assessment)),
],
),
title: new Text('Data'),
),
body: new TabBarView(
children: [
new RefreshIndicator(
key: _RIKey1,
onRefresh: _actualizoData1,
child: new ListView.builder(
padding: new EdgeInsets.only(top: 5.0),
itemCount: linea_reservas.length * 2,
itemBuilder: (BuildContext context, int position) {
if (position.isOdd) return new Divider();
final index = position ~/ 2;
return _buildRow(index);
}),
),
new RefreshIndicator(
key: _RIKey2,
onRefresh: _actualizoData2,
child: new ListView.builder(
padding: new EdgeInsets.only(top: 8.0),
itemCount: linea_inouthouse.length * 2,
itemBuilder: (BuildContext context, int position) {
if (position.isOdd) return new Divider();
final index = position ~/ 2;
return _buildRowInOutHouse(index);
}),
),
new RefreshIndicator(
key: _RIKey3,
onRefresh: _actualizoData3,
child: new ListView.builder(
padding: new EdgeInsets.only(top: 5.0),
itemCount: linea_ocupacion.length * 2,
itemBuilder: (BuildContext context, int position) {
if (position.isOdd) return new Divider();
final index = position ~/ 2;
return _buildRowOcupacion(index);
}),
),
],
),
),
),
);
}
该应用程序可以运行,但是几次更改标签后,它因以下错误而崩溃:
I/flutter ( 5252): ══╡ EXCEPTION CAUGHT BY WIDGETS LIBRARY ╞═══════════════════════════════════════════════════════════
I/flutter ( 5252): The following assertion was thrown building NotificationListener<KeepAliveNotification>:
I/flutter ( 5252): Multiple widgets used the same GlobalKey.
I/flutter ( 5252): The key [LabeledGlobalKey<RefreshIndicatorState>#7bd42] was used by multiple widgets. The parents of
I/flutter ( 5252): those widgets were:
I/flutter ( 5252): - RepaintBoundary-[<[LabeledGlobalKey<RefreshIndicatorState>#7bd42]>](renderObject:
I/flutter ( 5252): RenderRepaintBoundary#60a4a DETACHED)
I/flutter ( 5252): - RepaintBoundary-[<[LabeledGlobalKey<RefreshIndicatorState>#7bd42]>](renderObject:
I/flutter ( 5252): RenderRepaintBoundary#c8cdb NEEDS-LAYOUT NEEDS-PAINT)
I/flutter ( 5252): A GlobalKey can only be specified on one widget at a time in the widget tree.
我在线搜索了一个发现了StackOverflow解决方案Multiple widgets used the same GlobalKey以使用自定义键的方法:
import 'package:flutter/widgets.dart';
class RIKeys {
static final riKey1 = const Key('__RIKEY1__');
static final riKey2 = const Key('__RIKEY2__');
static final riKey3 = const Key('__RIKEY3__');
}
现在它可以按预期工作了,但是我不确定如何在用户点击应用栏上的刷新按钮时在状态类上声明它并显示currentState.show():
GlobalKey<RefreshIndicatorState> _RIKey1 = new GlobalKey<RefreshIndicatorState>();
_RIKey1.currentState.show();
我不确定如何解决此问题,请提出建议。谢谢您的帮助。