Question

我正在将Sequelize.js与SQLite数据库一起使用，并且遇到了设置外键值的问题。我有以下代码：

const MessageModel = sequelize.define('MessageModel ', {
    uuid: DataTypes.STRING,
    authorId: DataTypes.STRING,
    // ... other props
  }, {});

const TodoModel = sequelize.define('TodoModel', {
    ownerId: DataTypes.STRING,
    status: {
      type: DataTypes.STRING,
      defaultValue: 'pending'
    }
  }, {});

TodoModel.belongsTo(MessageModel , {
    foreignKey: {
        name: 'messageId',
        field: 'messageId',
        allowNull: false
    },
    targetKey: 'uuid'
});

MessageModel.create({
   uuid: 'testUUIDForExample'
   // other props
}).then(message => {

   console.log(`Message's created successful`);

   TodoModel.create({
      ownerId: 'id-string',
      status: 'test-status',
      messageId: 'testUUIDForExample'
   })
})

Sequelize在数据库中创建MessageModel行，但是在尝试使用此err生成TodoModel时会失败：

DatabaseError: SQLITE_ERROR: foreign key mismatch - "TodoModel" referencing "MessageModel "
    at Query.formatError (C:\Users\lrsvo\web-development\projects\platoon-web-electron\node_modules\sequelize\lib\dialects\sqlite\query.js:432:16)
    at Query._handleQueryResponse (C:\Users\lrsvo\web-development\projects\platoon-web-electron\node_modules\sequelize\lib\dialects\sqlite\query.js:77:18)
    at afterExecute (C:\Users\lrsvo\web-development\projects\platoon-web-electron\node_modules\sequelize\lib\dialects\sqlite\query.js:260:31)
    at Statement.errBack (C:\Users\lrsvo\web-development\projects\platoon-web-electron\node_modules\sqlite3\lib\sqlite3.js:16:21)

Err.original.message: "SQLITE_ERROR: foreign key mismatch - "TodoModel" referencing "MessageModel"

生成的SQL：

"INSERT INTO `TodoModel` (`id`,`ownerId`,`status`,`createdAt`,`updatedAt`,`messageId`) VALUES (NULL,$1,$2,$3,$4,$5);"

我的TodoModel表如下：

CREATE TABLE "TodoModel" (
    "id"            INTEGER PRIMARY KEY AUTOINCREMENT,
    "ownerId"   VARCHAR(255),
    "status"    TEXT DEFAULT 'pending',
    "createdAt" DATETIME NOT NULL,
    "updatedAt" DATETIME NOT NULL,
    "messageId" VARCHAR(255) NOT NULL,
    FOREIGN KEY("messageId") REFERENCES "MessageModel"("uuid") ON DELETE NO ACTION ON UPDATE CASCADE
);

我不知道为什么会发生错误并需要帮助，因为我在这个ORM中是虚拟的。

我在SQLite中使用“ sequelize”：“ ^ 5.1.0” 。

MyConfig文件：

const Sequelize = require("sequelize");
const electron = require('electron');
const storagePath = electron.app.getPath('userData') + '/plt.db';

module.exports = {
  development: {
    dialect: "sqlite",
    storage: storagePath,
    username: null,
    password: null,
    operatorsAliases: Sequelize.Op,
    define: { freezeTableName: true },
    query: { raw: true }, // Always get raw result
    logging: true,
  },
};

Answer 1

这里有很多事情。首先，如果要在MessageModel上使用uuid作为主键，则必须对其进行定义，否则将有一个默认的id字段。

const MessageModel = sequelize.define('MessageModel ', {
  uuid:{ // if this is your primary key you have to define it
    type: DataTypes.STRING,  //there is also DataTypes.UUID
    allowNull: false,
    primaryKey: true,
    unique: true
  }, 
  authorId: DataTypes.STRING,
  // ... other props
}, {});

然后在TodoModel上，将messageId关联设置为整数。要将其更改为字符串，必须在模型上定义字段，并在关联上将其用作外键。

const TodoModel = sequelize.define('TodoModel', {
  ownerId: DataTypes.STRING,
  status: {
    type: DataTypes.STRING,
    defaultValue: 'pending'
  },
  messageId: { //you also have to add the field on your model and set it as STRING, because on the association Sequelize by default is going to use INTEGER
    type: DataTypes.STRING,
    allowNull: false
  }
}, {});

TodoModel.belongsTo(MessageModel , {
  as: 'Message',
  foreignKey: 'messageId', // and you only set the foreignKey - Same name as your field above
});

在外键列中设置值的问题

1 个答案: