Question

我敢肯定，有更好的方法可以做最后的陈述。只是尝试检查是否在weekday或weekend中找到了dayOfWeek

到目前为止，我的代码：

dayOfWeek = input('What day is it?\n')

weekDay = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday']
weekend = ['Saturday', 'Sunday']


for i in range(5) and k in range(2):
    if dayOfWeek != weekDay[i] and dayOfWeek != weekend[k]:
        print("You didn't enter a Day of the week")

Answer 1

要检查某项是否在列表中，只需使用in运算符：

if not(DayOfWeek in weekend or DayOfWeek in weekday):
   print('You did not enter a day!')

Answer 2

您的尝试被解析为

for i in (range(5) and (k in range(2))):

，似乎k是先前分配的。 range(5)本身是真实的，所以and表达式的结果就是比较 k in range(2)的真实性。

将列表（或更确切地说，它们的迭代器）与itertools.chain绑定在一起，然后使用not in：

from itertools import chain

if dayOfWeek not in chain(weekDay, weekend):
    print("You didn't enter a Day of the week")

对于范围（5）中的i和范围（2）中的k：TypeError：'bool'对象不可迭代

2 个答案: