我遇到此代码问题:
def stupid_function():
try:
stupid_instruction1()
stupid_instruction2()
except:
pass
当看到stupid_instruction1()
中的错误时,它甚至不会尝试运行stupid_instruction2()
。有什么办法吗? (谢谢)
答案 0 :(得分:0)
您可以在两个不同的try块中运行这两个函数:
def stupid_function():
try:
stupid_instruction1()
except:
pass
try:
stupid_instruction2()
except:
pass
需要说明的是,您实际上不应排除所有错误,而应该仅排除特定错误。
答案 1 :(得分:0)
stupid_instruction2()
是否需要尝试?
如果可以,我建议将try/catch
放在要调用的函数中(如果它是您自己的函数)。如果不是您自己的函数,则将其包装如下:
def my_stupid_instruction2():
try:
stupid_instruction2()
except:
pass
如果您想让stupid_instruction2()
被呼叫,无论如何都可以这样做。
示例:
def stupid_function():
try:
stupid_instruction1()
except: # As Luke pointed out, it is bad practice to do a general exception
pass
finally:
stupid_instruction2() # This will be run regardless if the try fails