Question

我正在逐行读取文件。我使用一个函数在一行中查找指定的字符。

def find_all(a_str, sub):
    start = 0
    while True:
        start = a_str.find(sub, start)
        if start == -1: return
        yield start
        start += len(sub)

with open("file.txt", 'r', encoding='utf-8') as f:
    for line in f:                                                              
        a = list(find_all(line,"==")

这很好用，它将找到“ ==”，但是我实际上需要它来查找在使用时以某种方式省略的空格：

a = list(find_all(line," "))

我需要做些什么改变才能找到空间？

Answer 1

我不明白，这很完美：

list(find_all('This works perfectly doesn t it ?'," "))
[4, 10, 20, 26, 28, 31]

您能提供样品数据吗？也许您的空格是特殊字符？

我想你也看到了，但是以防万一：Find all occurrences of a substring in Python

Answer 2

如上面的@Hoog所述，您在代码末尾缺少括号。

def find_all(a_str, sub):
    start = 0
    while True:
        start = a_str.find(sub, start)
        if start == -1: return
        yield start
        start += len(sub)

with open("file.txt", 'r', encoding='utf-8') as f:
    for line in f:                                                              
        a = list(find_all(line,"==")) # << Right here

在文件的一行中查找空间

2 个答案: