我试图从双向链接列表中提取第一个节点，然后显示更改，但是在调用函数extractNode之后，它会检索正确的节点，但是列表的属性会获得一些随机值。谁能告诉我如何解决这个问题？
struct Train {
int code;
char* name;
};
struct node {
Train info;
node* next;
node* prev;
};
struct DoubleLinkedList {
node* first;
node* last;
};
Train createTrain(int cod, const char* name) {
Train t;
t.code = cod;
t.name = (char*)malloc(sizeof(char)*(1 + strlen(name)));
strcpy(t.name, name);
return t;
}
node* createNode(Train t, node* next, node* prev) {
node* nou = (node*)malloc(sizeof(node));
nou->info = t;
nou->next = next;
nou->prev = prev;
return nou;
}
DoubleLinkedList insertAtTheBeginning(DoubleLinkedList list,Train a) {
node* newNode = createNode(a, list.first, NULL);
if (list.first) {
newNode->next = list.first;
list.first->prev = newNode;
list.first = newNode;
}
else {
list.first = newNode;
list.last = newNode;
}
return list;
}
void displayTrain(Train t) {
printf("\n name: %s , code:%d \n", t.name, t.code);
}
void crossDoubleLinkedList(DoubleLinkedList list) {
node* temp = list.first;
while (temp) {
displayTrain(temp->info);
temp = temp->next;
}
}
node* extractNode(DoubleLinkedList list, int cod) {
node* extractedNode = NULL;
if (list.first == NULL) { return extractedNode; }
if (list.first->info.code == cod) {
node* extractedNode = createNode(createTrain(list.first->info.code, list.first->info.name), list.first->next, NULL);
list.first->next->prev = NULL;
node* copy = list.first;
list.first = list.first->next;
free(copy->info.name);
free(copy);
copy = NULL;
return extractedNode;
}
}
void main() {
DoubleLinkedList list;
list.first = NULL;
list.last = NULL;
list = insertAtTheBeginning(list, createTrain(1, "train1"));
list = insertAtTheBeginning(list, createTrain(2, "train2"));
crossDoubleLinkedList(list);
node* d = extractNode(list, 2);
crossDoubleLinkedList(list);
system("pause");
};
我希望列表中只有train1，但是它有 ：信息{code = -572662307 name = 0xdddddddd}火车