我正在尝试从System.Windows.Controls.Image
转换为byte[]
而我不知道Image类中哪种方法可以帮助这个场景,顺便说一下我真的不知道该怎么做,因为我的LINQ模型字段显示为Binary
类型,如果我想将其保存为byte[]
类型,我必须更改此内容吗?
我在这里发现了代码,但没有使用WPF:
Bitmap newBMP = new Bitmap(originalBMP, newWidth, newHeight);
System.IO.MemoryStream stream = new System.IO.MemoryStream();
newBMP.Save(stream, System.Drawing.Imaging.ImageFormat.Bmp);
PHJProjectPhoto myPhoto = new PHJProjectPhoto {
ProjectPhoto = stream.ToArray(), // <<--- This will convert your stream to a byte[]
OrderDate = DateTime.Now,
ProjectPhotoCaption = ProjectPhotoCaptionTextBox.Text,
ProjectId = selectedProjectId
};
答案 0 :(得分:32)
真正的解决方案...当你的ORM上的数据库映射字段是Byte [] / byte [] / Bynary
时,如果想从System.Windows.Control.Image保存jpg图像public byte[] getJPGFromImageControl(BitmapImage imageC)
{
MemoryStream memStream = new MemoryStream();
JpegBitmapEncoder encoder = new JpegBitmapEncoder();
encoder.Frames.Add(BitmapFrame.Create(imageC));
encoder.Save(memStream);
return memStream.ToArray();
}
致电:
getJPGFromImageControl(firmaUno.Source as BitmapImage)
希望有助于:)
答案 1 :(得分:13)
我不知道你的Image是如何声明的,但假设我们有这个XAML声明:
<Image x:Name="img">
<Image.Source>
<BitmapImage UriSource="test.png" />
</Image.Source>
</Image>
然后你可以将test.png的内容转换成这样的字节数组:
var bmp = img.Source as BitmapImage;
int height = bmp.PixelHeight;
int width = bmp.PixelWidth;
int stride = width * ((bmp.Format.BitsPerPixel + 7) / 8);
byte[] bits = new byte[height * stride];
bmp.CopyPixels(bits, stride, 0);
答案 2 :(得分:2)
public partial class MainWindow : Window
{
public MainWindow()
{
InitializeComponent();
}
private void btnBrowse_Click(object sender, RoutedEventArgs e)
{
var of = new OpenFileDialog();
of.Filter = "Image files (*.png;*.jpeg)|*.png;*.jpeg|All files (*.*)|*.*";
var res = of.ShowDialog();
if (res.HasValue)
{
imgPreview.Source = new BitmapImage(new Uri(of.FileName));
var t = Utils.ConvertBitmapSourceToByteArray(imgPreview.Source as BitmapSource);
var d = Utils.ConvertBitmapSourceToByteArray(new BitmapImage(new Uri(of.FileName)));
var s = Utils.ConvertBitmapSourceToByteArray(imgPreview.Source);
var enc = Utils.ConvertBitmapSourceToByteArray(new PngBitmapEncoder(), imgPreview.Source);
//imgPreview2.Source = Utils.ConvertByteArrayToBitmapImage(enc);
imgPreview2.Source = Utils.ConvertByteArrayToBitmapImage2(enc);
//var i = 0;
}
else
{
MessageBox.Show("Select a currect file...");
}
}
}
/ util.cs /
public class Utils
{
public static byte[] ConvertBitmapSourceToByteArray(BitmapEncoder encoder, ImageSource imageSource)
{
byte[] bytes = null;
var bitmapSource = imageSource as BitmapSource;
if (bitmapSource != null)
{
encoder.Frames.Add(BitmapFrame.Create(bitmapSource));
using (var stream = new MemoryStream())
{
encoder.Save(stream);
bytes = stream.ToArray();
}
}
return bytes;
}
public static byte[] ConvertBitmapSourceToByteArray(BitmapSource image)
{
byte[] data;
BitmapEncoder encoder = new JpegBitmapEncoder();
encoder.Frames.Add(BitmapFrame.Create(image));
using (MemoryStream ms = new MemoryStream())
{
encoder.Save(ms);
data = ms.ToArray();
}
return data;
}
public static byte[] ConvertBitmapSourceToByteArray(ImageSource imageSource)
{
var image = imageSource as BitmapSource;
byte[] data;
BitmapEncoder encoder = new JpegBitmapEncoder();
encoder.Frames.Add(BitmapFrame.Create(image));
using (MemoryStream ms = new MemoryStream())
{
encoder.Save(ms);
data = ms.ToArray();
}
return data;
}
public static byte[] ConvertBitmapSourceToByteArray(Uri uri)
{
var image = new BitmapImage(uri);
byte[] data;
BitmapEncoder encoder = new JpegBitmapEncoder();
encoder.Frames.Add(BitmapFrame.Create(image));
using (MemoryStream ms = new MemoryStream())
{
encoder.Save(ms);
data = ms.ToArray();
}
return data;
}
public static byte[] ConvertBitmapSourceToByteArray(string filepath)
{
var image = new BitmapImage(new Uri(filepath));
byte[] data;
BitmapEncoder encoder = new JpegBitmapEncoder();
encoder.Frames.Add(BitmapFrame.Create(image));
using (MemoryStream ms = new MemoryStream())
{
encoder.Save(ms);
data = ms.ToArray();
}
return data;
}
public static BitmapImage ConvertByteArrayToBitmapImage(Byte[] bytes)
{
var stream = new MemoryStream(bytes);
stream.Seek(0, SeekOrigin.Begin);
var image = new BitmapImage();
image.BeginInit();
image.StreamSource = stream;
image.EndInit();
return image;
}
}
答案 3 :(得分:1)
public byte[] BufferFromImage(BitmapImage imageSource)
{
Stream stream = imageSource.StreamSource;
byte[] buffer = null;
if (stream != null && stream.Length > 0)
{
using (BinaryReader br = new BinaryReader(stream))
{
buffer = br.ReadBytes((Int32)stream.Length);
}
}
return buffer;
}
将是另一种方式,但区别在于它比第一个解决方案
具有更少的字节[x]答案 4 :(得分:1)
这对我有用:
AFNetworking
答案 5 :(得分:1)
您也可以使用BitmapSources的CopyPixels方法
int stride = snapshot.PixelWidth * (snapshot.Format.BitsPerPixel / 8);
byte[] data = new byte[stride * snapshot.PixelHeight];
snapshot.CopyPixels(data, stride, 0);
var memoryStream = new MemoryStream(data);
答案 6 :(得分:0)
我喜欢命名空间中的编码器和解码器:System.Windows.Media.Imaging
public static class Extensions {
public static byte[] ToByteArray(this BitmapSource bitmapSource) {
var encoder = new JpegBitmapEncoder();
encoder.Frames.Add(BitmapFrame.Create(bitmapSource));
using (var stream = new MemoryStream()) {
encoder.Save(stream);
return stream.ToArray();
}
}
public static BitmapSource ToBitmapSource(this byte[] bytes) {
using (var stream = new MemoryStream(bytes)) {
var decoder = new JpegBitmapDecoder(stream, BitmapCreateOptions.None, BitmapCacheOption.Default);
return decoder.Frames.First();
}
}
}
你可以像这样使用它:
var bytes = bitmapSource.ToByteArray();
或者像这样:
var bitmapSource = bytes.ToBitmapSource();