用空格替换换行符，直到遇到第二个双引号

Question

我想逐行读取数据，在哪里找到双引号，我想用空格替换换行符，直到遇到第二个双引号，如

090033ec82b13639,CPDM Initiated,Logistical,"There corrected.",Gul Y Serbest,Urology
090033ec82ae0c07,Initiated,NA,"
To   local testing Rohit  3 to 4.",Julienne B Orr,Oncology
090033ec82b35fd0,Externally Initiated,NA,regulatory agency requests,Kenneth A Lord,Oncology

就像上面的数据第二行一样，它在第三行中找到双引号（打开）并关闭双引号，因此我们需要将这些行合并为一个空格，如下所示：

> 090033ec82b13639,CPDM Initiated,Logistical,"There corrected.",Gul Y
> Serbest,Urology 090033ec82ae0c07,Initiated,NA,"To   local testing
> Rohit  3 to 4.",Julienne B Orr,Oncology 090033ec82b35fd0,Externally
> Initiated,NA,regulatory agency requests,Kenneth A Lord,Oncology

在linux命令中，操作系统是solaris

awk '/^"/ {if (f) print f; f=$0; next} {f=f FS $0} END {print f}' file

sed -r 'H;1h;$!d;x; :a; s/(\t *"[^"]*)\n/\1 /; ta' file