Question

我的问题是要知道，如果jms队列（Wildfly 10）被高度填充，我该如何处理服务器上的负载。问题是消息不断被添加到JMS队列中，但它们是一一处理的。编写的逻辑是仅一一处理消息。我们无法一次处理多个消息，因为逻辑无法更改。但这会导致服务器上的负载增加，因为队列中加载了许多消息。此时我该如何管理队列。

这是我用于生产和消费的示例代码：-

以下代码每隔100毫秒运行一次计划，并从数据库中提取100条消息并发送到队列。

Arraylist arrMessages = GetMessagesFromdatabase（）;

for（MessageObject obj：arrMessages）sendMessagetoQueue（obj）;

生产者代码：-

void sendMessagetoQueue(MessageObject messageObject){
        ConnectionFactory connectionFactory = JMSConstants.getConnFactory.getJmsConnectionFactory();
            Context initialContext = JMSConstants.getConnFactory.getInitialcontext();
            Connection connection = null;

            String destinationName = "java:/jms/queue/Queue";
            MessageProducer publisher = null;
            Session session = null;

            try {

                connection = connectionFactory.createConnection();

                Queue queue = (Queue) initialContext
                        .lookup(destinationName);

                session = connection.createSession(false, Session.AUTO_ACKNOWLEDGE);

                publisher = session.createProducer(queue);

                connection.start();

                ObjectMessage objMessage = session.createObjectMessage(messageObject);

                publisher.send(objMessage);
                } catch (Exception exc) {
                exc.printStackTrace();
                LOG.error(exc);
            }
}

然后另一个时间表每100毫秒运行一次，以消耗队列中的消息并将其转发以进行逐一处理。

消费者代码：-

ConnectionFactory connectionFactory = JMSConstants.getConnFactory.getJmsConnectionFactory();
        Context initialContext = JMSConstants.getConnFactory.getInitialcontext();
        Connection connection = null;
        String destinationName = "java:/jms/queue/Queue";
        Session session = null;
        MessageConsumer consumer = null;
        Boolean checkFlag = true;
        QueueBrowser queueBrowserconnect = null;
        try {



                connection = connectionFactory.createConnection();

                Queue queue = (Queue) initialContext.lookup(destinationName);

                session = connection.createSession();
                consumer = session.createConsumer(queue);
                Queue senderqueueconnect = (Queue) initialContext.lookup(senderQueueconnect);
                queueBrowserconnect = session.createBrowser(senderqueueconnect);

                connection.start();


                ObjectMessage objectMessage = (ObjectMessage) consumer.receive(1);

                if (objectMessage != null) {

                    objectMessage.acknowledge();

                    MessageObject messageobject= (MessageObject) objectMessage.getObject();

                    //Send object for processing
                    messageService.processInputFromQueue(messageobject);

                }


        } catch (Exception exc) {
            exc.printStackTrace();
            LOG.error(exc.getMessage());
        }

如何有效处理JMS队列，避免服务器负载

0 个答案: