Question

我正在创建一个React Native应用程序，我想将应用程序的所有内容包装在一个标签中。

我可以用标签包裹每个页面，但这不是一个很干净的解决方案。

#include <iostream>using namespace std;

struct node {
int data;
node* prev;
node* next;
};

node* find(int,node*&);
void afterElement(int,int,node*&,node*&,node* (*find)(int, node*&));

int main() {
    node* head = NULL;
    node* tail = NULL;
    // The program itself has a menu that allows for input of value in list but
    // for the sake of relevancy and shortness of code I dropped it out from here

    int x, y;
    cout << "Insert 2 values: value you wish to insert, and value you wish to insert it after. ";
    cin >> x;
    cin >> y;
    afterElement(x,y,head,tail,find); // modified the passing argument
    return 0;
}

node* find(int x,node*& head) {
    node* curr = head;
    while ((curr != NULL) && (curr->data != x))
        curr = curr->next;
    return curr;
}

void afterElement(int x,int after,node*& head,node*& tail,node* (*find)(int x, node*& head)) {
node* N;
node* compared = (*find)(after,head);
N->data = x;
if (compared == NULL)
    cout << "There is no element " << after << " in the list!\n";
else {
    if (compared->next == NULL) {
        compared->next = N;
        N->prev = compared;
        N->next = NULL;
        tail = N;
    } else {
        compared->next->prev = N;
        N->next = compared->next;
        compared->next = N;
        N->prev = compared;
    }
}
}

我想要的工作是这样的：

const SimpleApp = StackNavigator({
    Home: {screen: HomeScreen},
    ...
});

AppRegistry.registerComponent('AFApplication', () => SimpleApp);

当然，代码是无效的，但是我想知道是否有一种方法可以达到预期的效果。

Answer 1

我认为您需要这样的东西：

const AppContainer = createAppContainer(AppNavigator);

export default class App extends React.Component {
  render() {
    return <AppContainer />;
  }
}

如果是的话，请检查react-navigation在项目中的设置。

祝你好运！

如何将整个应用程序包装在标签中？

1 个答案: