我尝试了一些研究,但没有发现与我的问题类似的东西。
我发现确实有很多检查表是否存在的方法,但是我想我的问题是我的表具有纯文本和类似Opened_". $DataDeConsulta ."
的变量
我尝试了以下代码,但可能会丢失一些内容。有人可以帮我吗?预先感谢!
if ($valid) {
$pdo = Database::connect();
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$stmt = $pdo->prepare("Select 1 from `Opened_". $DataDeConsulta ."`");
$stmt->execute(["Opened_". $DataDeConsulta .""]);
$count = $stmt->fetchColumn();
if ($count <= 0) {
$msg="No Data Found";
echo($msg);
}
else{
$sql = "SELECT * FROM filecleaner.`Opened_". $DataDeConsulta ."`";
$_SESSION['DataDeConsulta'] = $DataDeConsulta;
$query_result=$pdo->query($sql);
foreach ($pdo->query($sql) as $row) {
echo '<tr>';
echo '<td>'. htmlentities($row['Emails']) . '</td>';
echo ' ';
echo '</td>';
echo '</tr>';
}
Database::disconnect();
}
}
$Valid
设置在另一页上(只是一个错误验证)
答案 0 :(得分:0)
好吧,我找到了一种可以对某人有用的解决方案:
if (isset($valid)) {
$pdo = Database::connect();
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$stmt = $pdo->prepare("SELECT COUNT(*) FROM information_schema.tables WHERE table_schema = 'filecleaner' AND table_name = 'Opened_". $DataDeConsulta ."'");
$stmt->execute(["Opened_". $DataDeConsulta .""]);
$count = $stmt->fetchColumn();
if ($count <= 0) {
$msg="No Data Found";
echo($msg);
}
else{
$sql = "SELECT * FROM filecleaner.`Opened_". $DataDeConsulta ."`";
$_SESSION['DataDeConsulta'] = $DataDeConsulta;
$query_result=$pdo->query($sql);
foreach ($pdo->query($sql) as $row) {
echo '<tr>';
echo '<td>'. htmlentities($row['Emails']) . '</td>';
echo ' ';
echo '</td>';
echo '</tr>';
}
Database::disconnect();
}
}