Question

当前，我的代码是console.log("body:", body.readResults)。但是我不希望值t和r。如何取消选择它们并得到其余的？

"readResults": [
   {
       "id": "Channel1.Device1.Coil",
       "s": true,
       "r": "",
       "v": true,
       "t": 1553586722927
    }
]

Answer 1

您可以轻松做到：

function cleanMyResult(result) {
    const cleanResult = Object.assign({}, result); // this will preserve your original object, but it costs some performance
    delete cleanResult.t;
    delete cleanResult.r;
    return cleanResult;
}

const cleanedResults = body.readResults.map(cleanMyResult);
console.log(cleanedResults);

请同时检查很多已经很好的答案：

如何取消选择嵌套的JSON对象？

1 个答案: