Question

我想通过仅用字符串识别对象来获得List中某项的值

<!DOCTYPE suite SYSTEM "http://testng.org/testng-1.0.dtd">
<suite name="Personalization Test" verbose="1">
<listeners>
    <listener class-name="util.InvokedMethodListener"/>
</listeners>
<test name="Add Device" >
    <groups>
        <run>

            <include name="startAppiumServer"/>
            <include name="startApp_reset"/>
            <include name="welcome"/>
            <include name="tnc"/>
            <include name="permission"/>
            <include name="login"/>
            <include name="dashboard"/>

        </run>
    </groups>
    <classes>           
        <class name="test_cases.StartServer"/>
        <class name="test_cases.WelcomeTest"/>
        <class name="test_cases.TermAndConditionTest"/>
        <class name="test_cases.PermissionTest"/>
    </classes>
   </test>
</suite>

string A ="some_string";              
listobject.Add(fruit[0].A);

它不接受listobject.Add（fruit [0] .A）;作为标识符

Answer 1

从技术上讲，您可以尝试使用 Reflection ，即按其名称查找属性：

using System.Reflection;

...

private static T PropertyReader<T>(object value, string name) {
  if (null == value)
    throw new ArgumentNullException(nameof(value));
  else if (null == name)
    throw new ArgumentNullException(nameof(name));

  var prop = value.GetType().GetProperty(name);

  if (null == prop || !prop.CanRead)
    throw new ArgumentException($"property {name} has not been found.", nameof(name));

  return (T)(Convert.ChangeType(prop.GetValue(value, new object[0]), typeof(T)));
}

然后您可以按以下方式使用它：

listobject.Add(PropertyReader<string>(fruit[0], A));

通过字符串标识符获取list <t>的值

1 个答案: