JWT的decode()必须是数组错误类型

时间:2019-03-26 08:11:58

标签: php jwt slim

在这里,我有一些苗条的PHP代码可以登录,并且可以检查它是否对存储在标头中的JWT进行解码。

$app->post('/login', function ($request, $response) {

$input = $request->getParsedBody();
$settings = $this->get('settings'); // get settings array.
$sql = "SELECT id, password FROM users WHERE id= :id";
$sth = $this->db->prepare($sql);
$sth->bindParam("id", $input['id']);
$sth->execute();
$user = $sth->fetchObject();

// verify user id 
if(!$user) {
    return $this->response->withJson(['error' => true, 'message' => 'NO ID '], 404)->withHeader('Content-type', 'application/json;charset=utf-8', 404);
}
// Compare the input password and the password from database for a validation
if (strcmp($input['password'],$user->password)) {
    return $this->response->withJson(['error' => true, 'message' => 'These credentials do not match our records.'], 404)->withHeader('Content-type', 'application/json;charset=utf-8', 404);  
}

$payload = array(
    "iat" => time(),
    "exp" => time() + 36000,
    // "id" => $input['id']
    "context" => [
        "user" => [
            "id" => $input['id']
        ]
    ]
);

try {
    $token = JWT::encode($payload, $settings['jwt']['secret'],"HS256"); // $token store the token of the user
} catch (Exception $e) {
    echo json_encode($e);
}


return $this->response->withJson($payload,200)
                      ->withHeader('Content-type', 'application/json;charset=utf-8', 200)
                      ->withAddedHeader('Authorization', $token);
});


$app->get('/get', function ($request, $response) {

$jwt = $request->getHeader("Authorization"); 
$settings = $this->get('settings'); 

$token = JWT::decode($jwt, $settings['jwt']['secret'], "HS256"); // $token store the token of the user

if ($token) {
    return $this->response->withJson($token, 200)
    ->withHeader('Content-type', 'application/json;charset=utf-8', 200);
}

return $this->response->withJson($token,401)
                      ->withHeader('Content-type', 'application/json;charset=utf-8', 401);

});

但是当我尝试运行http://localhost:8080/get时,它将返回错误

  

传递给Firebase \ JWT \ JWT :: decode()的参数3必须为数组类型。

为什么会发生,我该如何解决?

2 个答案:

答案 0 :(得分:0)

尝试遵循错误提示:

$token = JWT::decode($jwt, $settings['jwt']['secret'], ["HS256"]);

您可以看到使用here

的示例

答案 1 :(得分:0)

如果我在同一函数中解码,则返回已解码的JWT,但如果我在其他函数中解码,则返回错误。如何将jwt传递给其他功能?

$app->post('/login', function ($request, $response) {

$key = "supersecretkeyyoushouldnotcommittogithub";

$input = $request->getParsedBody();
$settings = $this->get('settings'); // get settings array.
$sql = "SELECT id, password FROM users WHERE id= :id";
$sth = $this->db->prepare($sql);
$sth->bindParam("id", $input['id']);
$sth->execute();
$user = $sth->fetchObject();

// verify user id 
if(!$user) {
    return $this->response->withJson(['error' => true, 'message' => 'NO ID '], 404)->withHeader('Content-type', 'application/json;charset=utf-8', 404);
}
// Compare the input password and the password from database for a validation
if (strcmp($input['password'],$user->password)) {
    return $this->response->withJson(['error' => true, 'message' => 'These credentials do not match our records.'], 404)->withHeader('Content-type', 'application/json;charset=utf-8', 404);  
}

$payload = array(
    "iat" => time(),
    "exp" => time() + 36000,
    // "id" => $input['id']
    "context" => [
        "user" => [
            "id" => $input['id']
        ]
    ]
);

try {
    $token = JWT::encode($payload, $key); // $token store the token of the user
} catch (Exception $e) {
    echo json_encode($e);
}

// return $this->response->withJson($payload,200)
//                       ->withHeader('Content-type', 'application/json;charset=utf-8', 200)
//                       ->withHeader('Authorization', $token);

$decoded = JWT::decode($token, $key, array('HS256'));

print_r($decoded);


});